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Yakvenalex [24]
3 years ago
6

The cable supporting a 2125-kg elevator has a maximum strength of 21,750 n. what maximum upward acceleration can it give the ele

vator without breaking the cable?
Physics
1 answer:
Travka [436]3 years ago
5 0
Hi there you are in town
You might be interested in
if a body of mass 2kg moving with Velocity of 15m/s collides with a stationary body of same mass then after elastic collision 2n
pochemuha

Answer:

v = 15 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

P=m*v

where:

P = linear momentum [kg*m/s]

m = mass = 2 [kg]

v = velocity = 15 [m/s]

P=2*15\\P=30 [kg*m/s]

Since we know that momentum is conserved, that is, all momentum is transferred to the second body, we can determine the velocity of the second body, since the mass is equal to that of the first body.

30=2*v\\v = 30/2\\v = 15 [m/s]

5 0
3 years ago
How much work is done by a student carrying a 12 kg backpack while accelerating at a rate of 0.51 m/s2 over a distance of 5.0 m?
Klio2033 [76]

The amount of work done by the student in carrying the backpack is 30.6 J

<h3>Definition of workdone </h3>

Workdone is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = Force (F) × distance (d)

Wd = Fd

Also,

Force (F) = mass (m) × acceleration (a)

F = ma

Therefore,

Wd = (ma) × d

With the above formula, we can obtain the work done by the student.

<h3>How to determine the Workdone </h3>

From the question given above, the following data were obtained:

  • Mass (m) = 12 Kg
  • Acceleration (a) = 0.51 m/s²
  • Distance (d) = 5 m
  • Workdone (Wd) =?

Wd = (ma) × d

Wd = 12 × 0.51 × 5

Wd = 30.6 J

Learn more about workdone:

brainly.com/question/14667371

8 0
3 years ago
2. A proton and an electron are sitting 0.5m away from each other. What is the
Brrunno [24]

Answer:we can calculate the answer by the following formula;

Explanation:

3 0
3 years ago
The speed of a shallow water wave varies with
Sergio039 [100]
So we want to know how does the speed of a shallow water wave varies. If the wavelength is large enough in comparison to the depth of the water, meaning the wavelength is 20 times longer than the depth of water, the speed of a shallow water wave is the square root of gravity times water depth or: v=√(g*d), where v is speed of the wave, g=9.81 m/s^2 and d is water depth. 
5 0
3 years ago
Young's experiment is performed with light of wavelength 502nm from excited helium atoms. Fringes are measured carefully on a sc
alexandr402 [8]

Answer:

d = 1.30 mm

Explanation:

given,

wavelength of the light source (λ)= 502 nm

slits is separated (d) = ?

distance to form interference pattern(D) = 1.35 m  

20 th fringe

y = 10.4 mm = 0.0104 m

now,separation between to slits

 d = \dfrac{m\lambda\ D}{y}

where y is the fringe width

 d = \dfrac{20 \times 502\times 10^{-9}\ \times 1.35}{0.0104}

 d = \dfrac{13354\times 10^{-9}}{0.0104}

      d = 1.30 mm

separation between to slits is equal to d = 1.30 mm

8 0
3 years ago
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