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stellarik [79]
3 years ago
10

Two platoons line up for a tug of war. If both platoons have the same number of participants on a team, what other factor is cri

tical to either platoon's win?
A) age of men B) height of men C) total mass of the team D) condition of the ground
Physics
2 answers:
Serga [27]3 years ago
6 0
The best answer is C) total mass of the team. 

In tug of war, the mass of each team is a critical factor in determining which side wins. The team with greater mass will require greater force to move, and also is likely able to exert greater force on the other team due to the correlation between strength and mass. 
m_a_m_a [10]3 years ago
5 0
Yeah the answer is C hope this helps
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Answer:

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Explanation:

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Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n\times\dfrac{m}{V_{c}\times N_{A}}

n=\dfrac{\rho\timesV_{c}\times N}{m}....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100

\rho=5.98

We calculate the mass of the alloy

m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100

m=111.15

Put the value into the equation (I)

n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

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Answer:

Explanation:

Given

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Since there is no net acceleration therefore friction force will be zero

mathematically

f_r=ma

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