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Alik [6]
3 years ago
15

A horse walks along a straight path. it travels 3 in one second, 4 m in the next second, and 5 m in the third second. describe t

he horse's motion
Physics
1 answer:
Temka [501]3 years ago
3 0

Answer: The horse is moving with a uniform acceleration

Explanation:

According to the described situation, we are dealing with a <u>constant acceleration</u> (also called <u>uniform acceleration</u>), since the horse's velocity is changingn by a constant rate.

Let's prove it:

Firstly we are told the horse follows a straight path. In addition we are given its velocity:

3 m/s, then 4 m/s and 5 m/s

Since acceleration a is defined as the change of velocity in time we can calculate it:

a\frac{4 m/s-3 m/s}{1 s}=1m/s^{2} This is the horse's constant acceleration

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Your friend just challenged you to a race through an obstacle course. You know in order to beat him, you must run 30 meters with
seropon [69]

Answer:

Velocity = 0.5 m/s South (A)

Explanation:

You need to determine the average rate of velocity.  

The equation you will use is velocity = displacement/time

The displacement is 30m South.

The time is 60 seconds.

Plug into the equation  Velocity = 30m South/60 s

Velocity = 0.5 m/s South

3 0
3 years ago
A cat is shot horizontally out of a cannon that is on top of a 125 meter tall cliff. If the cat lands 286 m away from the base o
Elden [556K]

The initial velocity of the cat is 56.6 m/s

Explanation:

The motion of the cat is a projectile motion, consisting of:

- a uniform horizontal motion with constant velocity

- a vertical accelerated motion with constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:

s=ut+\frac{1}{2}at^2

where we have (choosing downard as positive direction)

s = 125 m is the vertical displacement of the cat

u = 0 is the initial vertical velocity

t is the time taken to reach the ground

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(125)}{9.8}}=5.05 s

Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by

v_x =\frac{d}{t}

where

d = 286 m is the horizontal distance travelled

t = 5.05 s is the time taken

Solving the equation,

v_x = \frac{286}{5.05}=56.6 m/s

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0
3 years ago
Heat from the sun moves through space by the process of
klasskru [66]
I don't know what your options are, but heat moves from the sun moves in 3 ways: radiation, conduction, and convection. I hope this helps at least a little
7 0
3 years ago
Read 2 more answers
Help me quickly! please!!!
stepan [7]

Answer:

(a) 6,000,000J      

(b)  3,000,000J

(c)  For A 20,000W

But for B 10,000W

6 0
2 years ago
A 320-kg satellite experiences a gravitational force of 800 N. What is the radius of the satellite’s orbit? What is its altitude
Westkost [7]

Answer:

Radius of orbit = 3.992 × 10^{7} m

Altitude of Satellite =33541.9×  m

Explanation:

Formula for gravitational force for a satellite of mass m  moving in an orbit of radius r around a planet of mass M is given by;

F= G\frac{m M}{r^{2} }

Where G = Gravitational constant = 6.67408 × 10-11 \frac{m^{3} }{Kg sec^{2} }

We are given

F= 800 N

m = 320 Kg

M = 5.972 × 10^{24} Kg

G = 6.67408 × 10-11 \frac{m^{3} }{Kg sec^{2} }

We have to find radius r =?

putting values in formula;

==> 800 =6.67408 ×10^{-11}× 320 × 5.972 × 10^{24} / r^{2}

==> 800= 39.8576 × 10^{13} × 320 / r^{2}

==> 800 = 12754.43 × 10^{13} / r^{2}

==> r^{2} = 12754.43 × 10^{13} /800

==> r^{2}=15.94 × 10^{13}

==> r =  3.992 × 10^{7} m

==> r = 39920×10^{3} m

This is the distance of satellite from center of earth. To find altitude we need distance from surface of earth. So we will subtract radius of earth from this number to find altitude.

Radius of earth =6378.1 km = 6378.1 × 10^{3} m

Altitude = 39920×10^{3} - 6378.1 ×

3 0
3 years ago
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