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const2013 [10]
3 years ago
10

20. A semiconductor is a

Physics
1 answer:
Stells [14]3 years ago
5 0

Answer:

D. crystalline solid that conducts current under certain conditions

Explanation:

Semiconductors are crystalline solids that has the ability to conduct electrical currents but on certain conditions e.g heat. The conduction of semiconductors is less than that of conductors (metals) but more than insulators (nonmetals), hence, they are said to be intermediates of conductors and insulators in terms of electrical conductivity.

Examples of semiconductors are silicon, boron, carbon, germanium, arsenic etc.

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I WILL MARK YOU AS BRAINLIEST IF RIGHT
butalik [34]

Answer:

25.4 miles per hour

Explanation:

speed=distance/time

speen=524/20.6 hours

=25.4 miles per hour

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4 years ago
Which safety procedure should you follow after breaking a mercury thermometer?
agasfer [191]
B. move away from the mercury and notify the teacher :)

you should never use a broom to sweep mercury, it breaks the mercury in smaller droplets and spread them.
Pouring the mercury in the sink would likely be logged in the plumbing. and pickingthings up with the napkin may cause contamination and cuts from the glass.
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3 years ago
Practice physics chapter 3 grade 11 test
Ugo [173]

Board???    what you want??

6 0
4 years ago
A baseball is projected horizontally with an initial speed of 18.1 m/s from a height of 1.85 m. at what horizontal distance will
gtnhenbr [62]
1) The motion of the baseball consists of two separate motions along the horizontal (x) and vertical (y) axis. The position on the two directions at time t is given by:
x(t)=v_0t
y(t)=h- \frac{1}{2}gt^2
where the motion on the x-axis is a uniform motion with constant speed v_0=18.1 m/s, while the motion on the y-axis is a uniformly accelerated motion with constant acceleration g=9.81 m/s^2, and initial height h=1.85 m.

First of all, we can find the time t at which the ball reaches the ground by requiring y(t)=0:
0=h- \frac{1}{2}gt^2
t= \sqrt{ \frac{2h}{g} }= \sqrt{ \frac{2(1.85 m)}{9.81 m/s^2} }=  0.61 s

and if now we substitute this time into the equation for x(t), we find the horizontal distance covered during this time interval, which is the horizontal distance covered by the ball before hitting the ground:
x(t)=v_0 t=(18.1 m/s)(0.61 s)=11.04 m

2) Speed of the ball as it hits the ground
We need to find the components of the velocity on the two directions, at the istant when the ball hits the ground.
On the x-axis, the velocity is the same as the initial one: 
v_x=18.1 m/s
On the y-axis, the velocity is given by
v_y(t)=gt
If we substitute t=0.61 s (the time at which the ball reaches the ground), we find
v_y =gt=(9.81 m/s^2)(0.61 s)=6.0 m/s
And the speed of the ball is the magnitude of the resultant of the two components:
v= \sqrt{v_x^2+v_y^2}= \sqrt{(18.1 m/s)^2+(6.0 m/s)^2}=19.1 m/s
8 0
3 years ago
Read 2 more answers
Is there a formula for the 2nd Law of Therodynamics, is so name it?
IrinaK [193]

∆S>_closed integral of dQ/T

There are many equations for different situations of entropy but this is a general one

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4 years ago
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