Answer:
Mass percent of food dyes = 0.0616%
Explanation:
Given data:
Mass of candy = 47.9 g
Calories = 240
Mass of fat = 10 g
Mass of carbohydrate = 34 g
Mass of protein = 2 g
Mass of food dyes = 29.5 mg
Mass percent of food dyes = ?
Solution:
First of all we will convert the mg into g.
Mass of food dyes = 29.5 mg × 1g /1000 mg = 0.0295 g
Mass percent of food dyes = mass of food dyes / total mass× 100
Now we will put the values.
Mass percent of food dyes = 0.0295 g / 47.9 g × 100
Mass percent of food dyes = 0.000616 × 100
Mass percent of food dyes = 0.0616%
Answer:
The hydrogen ion concentrations associated with these pH value 7.35 is 
The hydrogen ion concentrations associated with these pH value 7.45 is 
.
Explanation:
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
1) pH = 7.35
Putting values in above equation, we get:
![7.35=-\log[H^+]](https://tex.z-dn.net/?f=7.35%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=4.467\times 10^{-8} M\approx 4.5\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D4.467%5Ctimes%2010%5E%7B-8%7D%20M%5Capprox%204.5%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.35 is
2) pH = 7.45
Putting values in above equation, we get:
![7.45=-\log[H^+]](https://tex.z-dn.net/?f=7.45%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=3.548\times 10^{-8}M \approx 3.6\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D3.548%5Ctimes%2010%5E%7B-8%7DM%20%5Capprox%203.6%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.45 is .
<span>1.) a. 20 ÷ 4 ? means ? × 4 = 20 </span>→ replace ? with 5.<span>
b. 2,725 ÷ 5 ? means ? × 5 = 2,725 </span>→ replace ? with 545<span>
c. ? ÷ 5 = 0 </span>→ replace ? with 0.
2) 1,475 / 25 = 59
They used 59 boxes for this year.
3) 18 per haircut ; 70 per perm
4,608 = 18h + 70(36)
4,608 - 2,520 = 18h
2,088 = 18h
2,088/18 = h
116 = h
Grace did 116 haircuts.
4) 575 + 13(118) = 575 + 1,534 = 2,109 total expense.
5) 2,240 miles / 320 miles = 7 tanks of gas used.
7 tanks * 39 = 273 cost of the gas used.
Answer:
The longest wavelength of radiation with enough energy to break a carbon–carbon bond is 343.75 nm.
Explanation:
E = hc/λ
E: energy = 348 000 J / 6.022 x 10²³ = 5.7788 x 10⁻¹⁹ J
h: Planck's constant = 6.62607004 × 10⁻³⁴ J.s
c: speed of light = 299 792 458 m / s
λ: wavelength
λ = hc/E
λ = (6.62607004 × 10⁻³⁴ J.s x 299 792 458 m / s) / 5.7788 x 10⁻¹⁹J
λ = 3.4375 x 10⁻⁷ m
λ = 343.75 nm
