By geometric and algebraic properties the angles BTC, TBC and TBC from the triangle BTC are 128°, 26° and 26°, respectively.
<h3>How to determine the angles of a triangle inscribed in a circle</h3>
According to the figure, the triangle BTC is inscribed in the circle by two points (B, C). In this question we must make use of concepts of diameter and triangles to determine all missing angles.
Since AT and BT represent the radii of the circle, then the triangle ABT is an <em>isosceles</em> triangle. By geometry we know that the sum of <em>internal</em> angles of a triangle equals 180°. Hence, the measure of the angles A and B is 64°.
The angles ATB and BTC are <em>supplmentary</em> and therefore the measure of the latter is 128°. The triangle BTC is also an <em>isosceles</em> triangle and the measure of angles TBC and TCB is 26°.
By geometric and algebraic properties the angles BTC, TBC and TBC from the triangle BTC are 128°, 26° and 26°, respectively.
To learn more on triangles, we kindly invite to check this verified question: brainly.com/question/2773823
Answer:
C: (1,3)
Step-by-step explanation:
If we count 1 to the right on the x-axis and count 3 up on the y-axis, we will end up at the point of intersection which is (1,3).
Well subtract 8 from 1000 and then do that five times. so 992,984,976,968, and 960<span />
You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)
