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2 years ago

How’s does my friend cell phone communicate with them? How does it speak with my voice to them?

Physics

1 answer:

castortr0y [4]2 years ago

5 0

Answer:

A microchip in the phone modulates (or varies) a radio wave using the electrical signal. The radio wave travels through the air to a nearby cell tower; the tower sends your voice to the person you are calling and the process is reversed so that the person on the other end can hear your voice.

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A long uniform wooden board (a playground see-saw) has a pivot point at its center. An older child of mass M=32 kg is sitting a

PIT_PIT [208]

Answer: $\frac{5L}{6}$

Explanation:

Given

Wooden board is pivoted at center and

Older child of mass $M=32\ kg$ is sitting at a distance of L from center

if two child of mass $\frac{M}{2}$ is sitting at a distance $\frac{L}{6}$ and $x$ (say) from pivot then net torque about pivot is zero

i.e.

$\Rightarrow \tau_{net}=MgL-\frac{M}{2}g\frac{L}{6}-\frac{M}{2}gx$

as $\tau_{net}=0$

Therefore

$MgL=\frac{M}{2}g\frac{L}{6}+\frac{M}{2}gx$

$L-\frac{L}{6}=x$

$x=\frac{5L}{6}$

Therefore another child is sitting at a distance of $\frac{5L}{6}$

3 0

3 years ago

When the temperature of matter decrease , the particles do what

Rom4ik [11]

Answer:

When the temperature decreases the particals start to slow down.

4 0

3 years ago

A 2.00 kg box slides on a rough, horizontal surface, hits a spring with a speed of 1.90 m/s and compresses it a distance of 10.0

oksian1 [2.3K]

Answer:

Explanation:

Given

mass of box $m=2\ kg$

speed of box $v=1.9\ m/s$

distance moved by the box $x=10\ cm$

coefficient of kinetic friction $\mu _k=0.66$

Friction force $f_r=\mu_kN$

$f_r=0.66\times mg$

$f_r=0.66\times 2\times 9.8=12.936 \N$

Kinetic Energy of box will be utilize to overcome friction and rest is stored in spring in the form of elastic potential energy

$\frac{1}{2}mv^2=f_r\cdot x+\frac{1}{2}kx^2$

$\frac{1}{2}\times 2\times 1.9^2=12.936\times 0.1+\frac{1}{2}\times k\times (0.1)^2$

$3.61-1.2936=0.005\times k$

$k=463.28\ N/m$

3 0

3 years ago

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A hole is punched at A in a plastic sheet by applying a 660-N force P to end D of lever CD, which is rigidly attached to the sol

olasank [31]

Answer:

hello your question lacks some data and required diagram

G = 77 GPa, т all = 80 MPa

answer : required diameter = 252.65 * 10-^3 m

Explanation:

Given data :

force ( P ) = 660 -N force

displacement = 15 mm

G = 77 GPa

т all = 80 MPa

i) Determine the required diameter of shaft BC

considering the vertical displacement ( looking at handle DC from free body diagram )

D' = 0.3 sin∅ , where D = 0.015

hence ∅ = 2.8659°

calculate the torque acting at angle ∅ of CD on the shaft BC

Torque = 660 * 0.3 cos∅

= 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N

hello attached is the remaining part of the solution

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3 years ago

Back in their laboratory, the team of scientists carefully measure the changes in density of a freshwater sample as they decreas

BabaBlast [244]

Answer: As the temperature of the water decreases from 20 degrees celsius to 4 degrees celsius, the density increases.

Explanation:

7 0

2 years ago

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