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-Dominant- [34]
3 years ago
10

PLEASE HELP ASAP!!!!!

Physics
1 answer:
liq [111]3 years ago
4 0

Answer:

r = 0.37 m

Explanation:

Use Coulomb's law to solve for r:

F = kq1q2/r^2

---> r^2 = kq1q2/F

= (8.99×10^9)(5.6×10^-4)(-2.1×10^-4)/(-7.7×10^3)

= 0.1373 m^2

or r = 0.37 m

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In a stationary situation, the weight of person is
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This is the weight "felt" by the scale, which is basically the normal reaction applied by the scale on the person, and which uses the value of g (9.81) as reference to convert the weight (602.8 N) into a mass (62 kg).

When the person is in the elevator, the scale says 77 kg. The scale is still using the same value of conversion (9.81), so the apparent weight "felt" by the scale is
W' = m'g=(77 kg)(9.81 m/s^2)=755.4 N
This is the normal reaction applied by the scale on the person, and which is directed upward. Besides this force, there is still the weight W of the person, acting downward. So, if we use Newton's second law:
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3 years ago
Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most o
8_murik_8 [283]

Answer:

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Rounding to the next integrer: 3.

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Answer:

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{\bold{\red{HOPE\:IT\:HELPS!}}}

\color{yellow}\boxed{\colorbox{black}{MARK\: BRAINLIEST!❤}}

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2 years ago
What is the relation between acceleration due to gravity and radius of the earth? ​
emmasim [6.3K]

Answer:

As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.

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Explanation:

Please Mark me brainliest

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3 years ago
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