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Delvig [45]
4 years ago
8

What do scientists do to easily share measurement data they can understand?

Physics
2 answers:
Airida [17]4 years ago
8 0
I think it'd be C.. I took a test that had this same question a couple yrs ago. So, I'm pretty sure its C. 
malfutka [58]4 years ago
3 0
These days, scientists all over the world use a standard system of measurements.  It's the SI or metric system.

What about scientists in the United States, Liberia, and Burma ? 
These three countries are the only ones in the world that haven't
adopted the metric system.  What do THEY do ?

Easy.  When scientists in those countries are off work, they use the
inches, yards, feet, quarts, miles and gallons that everybody around
them is using.  But when they go to work, they use the same metric
system that everyone else in the world is using.
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A camcorder has a power rating of 16 watts. If the output voltage from its battery is 7 volts, what current does it use?
GenaCL600 [577]

Power= current*voltage or P=IV

so 16 watts=I*7 volts

divide on both sides to isolate I so you get

I= 16/7 which is about 2.3 amps

8 0
3 years ago
If a runner does 1,500 J of work over 10.0 s, then how much power does she have?
erma4kov [3.2K]
I would say 150 joules, i don't know if its right though check
8 0
3 years ago
Read 2 more answers
If a particle undergoes shm with amplitude 0.21 m, what is the total distance it travels in one period?
Ymorist [56]
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
7 0
3 years ago
Suppose that on earth you can throw a ball vertically upward a distance of 1.20 m. Given that the acceleration of gravity on the
tatuchka [14]

Answer:

7.04 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement on Earth = 1.2 m

a = Acceleration due to gravity on Moon = 1.67 m/s²

a = Acceleration due to gravity Earth= 9.81 m/s²

Accelration going up is considered as negetive

Initial Velocity of the ball

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow -u^2=2\times -9.81\times 1.2-0^2\\\Rightarrow u=\sqrt{2\times 9.81\times 1.2}\\\Rightarrow u=4.85\ m/s

Assuming that the ball is thrown with the same velocity on the Moon, displacement of the ball is

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-4.85^2}{2\times -1.67}\\\Rightarrow s=7.04\ m

The displacement of the ball on the moon is 7.04 m

6 0
3 years ago
A woman and her dog are out for a morning run to the river, which is located 4.0 KM away. The woman runs at 2.5 M/S in a straigh
VLD [36.1K]

River shore is located at distance

d = 4 km

speed of the woman is given as

v_1 = 2.5 m/s

now the time taken by the woman to cover the distance is

t = \frac{d}{v}

t = \frac{4000}{2.5} = 1600 s

for the same time interval the dog will run to and fro with speed 4.5 m/s

so the total distance moved by the dog is given by

d = v* t

d = 4.5 * 1600

d = 7200 m

<em>so the total distance that dog will move is 7200 m or 7.2 km</em>

8 0
3 years ago
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