1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
quester [9]
3 years ago
5

If a true heading of 135° results in a ground track of 130° and a true airspeed of 135 knots results in a groundspeed of 140 kno

ts, the wind would be from
Physics
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

245.1° and 13 knots

Explanation:

The given parameters are;

The true heading = 135°

The resultant ground track = 130°

The true airspeed = 135 knots

The ground speed = 140 knots

Given that the true airspeed the ground speed and the wind direction and magnitude form a triangle, we have;

From cosine rule, we have;

a² = b² + c² - 2×b×c×cos(A)

Where

a = The magnitude of the wind speed in knot

b = The true airspeed = 135 knots

c = The ground speed = 140 knots

A = The angle in between the true heading and the resultant ground track heading = 5°

Which gives;

a² = 135² + 140² - 2×135×140×cos(5 degrees) = 168.84 knots²

a = √168.84 = 12.9934 ≈ 13 knots

We have;

135 × sin(135 degrees) - 140× sin(130 degrees) = -11.7868

135 × cos(135 degrees) - 140× cos(130 degrees) = -5.469

Tan(θ) = -11.8/-5.5 = 2.155

θ = tan⁻¹(2.155) = 65.108°

Given that the wind is moving in opposite direction (slowing down the airplane, we add 180°, to get

Therefore, the angle direction = 180 + 65.108 = 245.1

Therefore, we have;

245.1° and 13 knots

You might be interested in
Just like energy is <br> matter is lost through an ecosystem
Novosadov [1.4K]
Yes energy is reduced 
7 0
3 years ago
Read 2 more answers
Help quick<br> p;leaseeeeeeeeeeee its about direction and magnitude
KonstantinChe [14]

Explanation:

The net force of each square is the combination of the forces in each direction. The direction is the... direction the square would go in due to the net force. The magnitude of the net force is how large it is. So if you had a force pushing 2N to the left and 1N to the right, then the net force would be 1N to the left; because the two oppose eachother. If they were going in the same direction, then they'd add to each other. And perpendicular net forces (like one pushing up and another pushing left) can create net forces in diagonal directions.

I'm not going to do all of these for you because they're basically all the same thing and it's good practice for you anyway. But I'll do the first three just so you can get the idea:

1. The net force's magnitude is 4N and it's direction is to the right.

2. The net force's magnitude is 4N and it's direction is to the left.

3. The net force's magnitude is 0N and it has no direction because they are equal forces acting in opposite directions.

7 0
3 years ago
The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 10−31 kg from rest to 3 × 107 m/s within
zaharov [31]

Answer:

Electric field, E = 40608.75 N/C

Explanation:

It is given that,

Mass of electrons, m=9.1\times 10^{-31}\ kg

Initial speed of electron, u = 0

Final speed of electrons, v=3\times 10^7\ m/s

Distance traveled, s = 6.3 cm = 0.063 m

Firstly, we will find the acceleration of the electron using third equation of motion as :

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{(3\times 10^7)^2}{2\times 0.063}

a=7.14\times 10^{15}\ m/s^2

Now we will find the electric field required in the tube as :

ma=qE

E=\dfrac{ma}{q}

E=\dfrac{9.1\times 10^{-31}\times 7.14\times 10^{15}}{1.6\times 10^{-19}}

E = 40608.75 N/C

So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.

3 0
3 years ago
Which statement best describes an isolated system? (1 point)
bonufazy [111]

Answer:

idk

Explanation:

6 0
3 years ago
Read 2 more answers
What is the mass of a large ship that has a momentum of 1.60×109kg·m/s, when the ship is moving at a speed of 48.0 km/h? (b) Com
erastova [34]

a) The mass of the ship is 1.2\cdot 10^8 kg

b) The ship has a larger momentum than the shell

Explanation:

a)

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its velocity

For the ship in this problem, we have

p=1.60\cdot 10^9 kg m/s is the momentum

v=48.0 km/h \cdot \frac{1000 m/km}{3600 s/h}=13.3 m/s is the velocity

Solving for m, we find the mass of the ship:

m=\frac{p}{v}=\frac{1.60\cdot 10^9}{13.3}=1.2\cdot 10^8 kg

b)

The momentum of the artillery shell is given by

p=mv

where

m is its mass

v is its velocity

For the shell in this problem,

m = 1100 kg

v = 1200 m/s

Substituting,

p=(1100)(1200)=1.32\cdot 10^6 kg m/s

So, we see that the ship has a larger momentum.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
Other questions:
  • What is true about valence electrons?
    5·2 answers
  • Nuclear Energy definition ​
    8·1 answer
  • Martha is cycling at a speed of 20 kilometers per hour. How long will it take her to cover a distance of 60 kilometers? speed=di
    11·2 answers
  • You are measuring the mass of different chemicals to get ready to conduct an experiment.
    6·2 answers
  • Slow pain originating from an internal organ is often perceived as coming from an area of the body totally unrelated to the sour
    7·1 answer
  • A student is preparing to bake a cake at home and places several ingredients on the countertop to use. First he preheats the ove
    11·1 answer
  • A car has uniformly accelerated from rest to a speed of 25m/s after traveling 75m. What is its acceleration in m/s^2
    10·1 answer
  • An object is moving in a straight line at constant speed. A resultant torce begins to act upon
    6·1 answer
  • What does a polar molecule mean?
    5·1 answer
  • An angry physics student releases a wrecking ball as shown. The wrecking ball is just about to hit the building at the final tim
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!