Two tuning forks of frequency 480 hz and 484 hz are struck simultaneously. what is the beat frequency resulting from the two sou

Question

bonufazy [111]

3 years ago

13

Two tuning forks of frequency 480 hz and 484 hz are struck simultaneously. what is the beat frequency resulting from the two sou

nd waves?

Physics

1 answer:

umka21 [38] · Answer 1 · 2022-02-08T13:21:35+03:00

Ans: Beat frequency = $f_b$ = 4Hz

Explanation:
The beat frequency is equal to the absolute value of the difference in frequency of the two waves. In other words, the number of beats per second is equal to the difference in frequency. It is due to the destructive and constructive interference. <span>According to this interference, sound will be soft or loud.

Hence. the formula is:
</span>Beat frequency = $f_b = |f_2 - f_1|$
<span>
Since,
</span> $f_1 = 480Hz$
$f_2 = 484Hz$

Therefore,
Beat frequency = $f_b = |484 - 480|$

=> Beat frequency = $f_b = 4Hz$
-i