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KatRina [158]
3 years ago
5

Iron forms rust, expressed as: Fe2O3. Using information from the Periodic Table, what is the mass of one mole of Fe2O3?

Chemistry
2 answers:
nika2105 [10]3 years ago
8 0
The answer is C, 159.70g
sasho [114]3 years ago
6 0

Answer:

The correct answer is option C.

Explanation:

Atomic mass of iron =  55.845 g/mol

Atomic mass of oxygen = 15.999 g/mol

Mass of 1 mole of iron(III) oxide , Fe_2O_3:

2\times 55.845 g/mol+3\times 15.999 g/mol=159.687 g/mol

159.687 g/mol ≈ 159.70 g/mol

159.70 g/mol is the mass of one mole of iron(III) oxide.

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Calculate the molarity (M) of a 600 ml solution of 0.54 moles of H2SO4.
icang [17]
Molarity (concentration) can be calculated by the equation:
Concentration = moles / volume in L = 0.54 mol / 0.6 L = 0.9 M
Hope this helps!
8 0
3 years ago
At a certain temperature the vapor pressure of pure thiophene is measured to be . Suppose a solution is prepared by mixing of th
Lesechka [4]

Answer:

0.35 atm

Explanation:

It seems the question is incomplete. But an internet search shows me these values for the question:

" At a certain temperature the vapor pressure of pure thiophene (C₄H₄S) is measured to be 0.60 atm. Suppose a solution is prepared by mixing 137. g of thiophene and 111. g of heptane (C₇H₁₆). Calculate the partial pressure of thiophene vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal."

Keep in mind that if the values in your question are different, your answer will be different too. <em>However the methodology will remain the same.</em>

First we <u>calculate the moles of thiophene and heptane</u>, using their molar mass:

  • 137 g thiophene ÷ 84.14 g/mol = 1.63 moles thiophene
  • 111 g heptane ÷ 100 g/mol = 1.11 moles heptane

Total number of moles = 1.63 + 1.11 = 2.74 moles

The<u> mole fraction of thiophene</u> is:

  • 1.63 / 2.74 = 0.59

Finally, the <u>partial pressure of thiophene vapor is</u>:

Partial pressure = Mole Fraction * Vapor pressure of Pure Thiophene

  • Partial Pressure = 0.59 * 0.60 atm
  • Pp = 0.35 atm

3 0
3 years ago
NEED HELP ON 17,18,19,20,21,22,23. ONLY IF YOU ARE POSITIVE ABOUT THE ANSWER!!!!
Alex777 [14]

Answer:

17. D. Chemical change

18. C. Cell wall

19. D. To transfer matter and energy within and between organisms.

20. A. Transporting materials

21. C. Carbon dioxide

22. A. Cellular respiration

23. C. Produce food and give off oxygen

Explanation:

I have been able to supply the correct answers. The cell wall functions as a structure that provides structural support and protection to the cell. It is tough, flexible and at times rigid. In a chemical change, new materials with new properties are manufactured. So, the process of photosynthesis is a chemical change.

The endoplasmic reticulum actually transports material. It transports materials like protein and lipids made within the cell and sends it to where they are needed.

Carbon dioxide  is the the gas that animals give off and plants use it during photosynthesis. Cellular respiration involves the activities that result to the breaking down of food in order to release energy.

8 0
3 years ago
The average kinetic energy of the particles in an object is directly proportional to its
Galina-37 [17]
C. Temperature the average <span> kinetic energy of the particles in an object is directly proportional to its temperature </span>
6 0
3 years ago
Read 2 more answers
A sample of PCl5(g) was placed in an otherwise empty flask at an initial pressure of 0.500 atm and a temperature above 500 K. Ov
tia_tia [17]

Answer:

Kp = 0.81666

Explanation:

Pressure of PCl₅ = 0.500 atm

Considering the ICE table for the equilibrium as:

                     PCl₅ (g)      ⇔          PCl₃ (g) +       Cl₂ (g)

t = o               0.500

t = eq                -x                             x                      x

--------------------------------------------- --------------------------

Moles at eq: 0.500-x                       x                      x

       

Given the pressure of PCl₅ at equilibrium = 0.150 atm

Thus, 0.500 - x = 0.150

x = 0.350 atm

The expression for the equilibrium constant is:

K_p=\frac {P_{PCl_3}P_{[Cl_2}}{P_{PCl_5}}  

So,

K_p=\frac{x^2}{0.500-x}  

x = 0.350 atm

Thus,

K_p=\frac{{0.350}^2}{0.500-0.350}  

<u>Thus, Kp = 0.81666</u>

7 0
3 years ago
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