Question

When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction grating having a spacing between adjacent lines of 4082 nm is used in an experiment to study the visible spectrum of hydrogen. The hydrogen light is sent through the grating and the light emitted by the hydrogen at 656 nm is observed. At what angle does the third order bright fringe occur for this specific wavelenth of light occur

Answer 1

Answer:

28.82°

Explanation:

the equation for a diffraction grating is given by

$dsin\theta=m\lambda$

where d is the distance between slits, m is the order of the bright fringe and lambda is the wavelength of the light. By replacing we obtain:

$sin\theta=\frac{m\lambda}{d}=\frac{(3)(656nm)}{4082nm}=0.482\\\\\theta=sin^{-1}(0.482)=28.82\°$

Then, for the third fringe the angle is 28.82°.

hope this helps!!