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3 years ago

In which season of the year is a forest most likely to look very stark?

Physics

2 answers:

kolbaska11 [484]3 years ago

8 0

B. Winter Would be ur answer

Hope I helped:P

Zina [86]3 years ago

3 0

<h3><u>Answer;</u></h3>

B. winter

<h3><u>Explanation;</u></h3>

<em><u>Winter happens to be the coldest season of the year in polar and temperate zones. This season occurs before spring and after autumn each year. </u></em>
<em><u>Winter temperatures are often below freezing. Since the winter is cooler, this encourages trees to shed their leaves. Trees and plants stop growing during this season.</u></em>
<em><u>Therefore, it is during winter season when forests would look very stark.</u></em>

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Why is cathode positive in leclanche cell??

laila [671]

Answer:

Because the zinc is reluctant

Explanation:

A leclanche cell contains a conducting solution (electrolyte) of ammonium chloride, a cathode (positive terminal) of carbon, a depolarizer of manganese dioxide (oxidizer), and an anode (negative terminal) of zinc (reductant).

As the Zn2+ ions move away from the anode, leaving their electrons on its surface,

Zn → Zn2+ + 2e−

the anode becomes more negatively charged than the cathode. When the cell is connected to an external electrical circuit, the excess electrons on the zinc anode flow through the circuit to the carbon rod, the movement of electrons forming an electric current.

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3 years ago

A-delta fibers : A) are small, myelinated fibers. B) transmit pain signals at a slower rate than C-fibers. C) typically transmit

daser333 [38]

Answer:

Explanation:

Aδ fibers carry cold, pressure, and acute pain signals, and because they are thin (2 to 5 μm in diameter) and myelinated, they send impulses faster than unmyelinated C fibers, but more slowly than other, more thickly myelinated group A nerve fibers. Their conduction velocities are moderate.

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3 years ago

11. A cyclist accelerates from 0 m/s to 10 m/s in 3 seconds. What is his acceleration ? Is this acceleration higher than that of

Marat540 [252]

$a = \frac{v - u}{t}$

v = final velocity

u = initial velocity

t = time taken

the acceleration of the cyclist is

$\frac{10 - 0}{3} = 3.333333....$

approximately 3.33 m/s^2

the acceleration of the car is

$\frac{40 - 0 }{8} = 5.0$

5.0 m/s^2

$5.0 > 3.33 \\ so \: the \: answer \: is \: no$

6 0

3 years ago

This list shows the heights in feet of the 30 tallest mountains in the United States. 14,269 14,361 14,470 14,831 16,237 14,270

antoniya [11.8K]

Answer: a. Frequency. 20, 4, 3, 1, 1, 0, 1

Explanation:

Interval(Height in feet) - - - - - - - - frequency

14000 - 14999 - - - - - - - - - - - - - - - 20

15000 - 15999 - - - - - - - - - - - - - - - 4

16000 - 16999 - - - - - - - - - - - - - - - 3

17000 - 17999 - - - - - - - - - - - - - - - 1

18000 - 18999 - - - - - - - - - - - - - - - 1

19000 - 19999 - - - - - - - - - - - - - - - 0

20000 - 20999 - - - - - - - - - - - - - - 1

Frequency : (20, 4, 3 1, 1, 0, 1)

8 0

3 years ago

Exoplanets (planets outside our solar system) are an active area of modern research. Suppose astronomers find such a planet that

Leno4ka [110]

Answer:

8.829 m/s²

Explanation:

M = Mass of Earth

m = Mass of Exoplanet

$g_e$ = Acceleration due to gravity on Earth = 9.81 m/s²

g = Acceleration due to gravity on Exoplanet

$m=M-0.1M\\\Rightarrow m=0.9M$

$g_e=G\frac{M}{r^2}$

$g=G\frac{0.9M}{r^2}$

Dividing the equations we get

$\frac{g}{g_e}=\frac{G\frac{0.9M}{r^2}}{G\frac{M}{r^2}}\\\Rightarrow \frac{g}{g_e}=0.9\\\Rightarrow g=0.9g_e\\\Rightarrow g=0.9\times 9.81\\\Rightarrow g=8.829\ m/s^2$

Acceleration due to gravity on the surface of the Exoplanet is 8.829 m/s²

3 0

3 years ago