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VladimirAG [237]
4 years ago
9

In which season of the year is a forest most likely to look very stark?

Physics
2 answers:
kolbaska11 [484]4 years ago
8 0
B. Winter Would be ur answer

Hope I helped:P 
Zina [86]4 years ago
3 0
<h3><u>Answer;</u></h3>

B. winter

<h3><u>Explanation;</u></h3>
  • <em><u>Winter happens to be the coldest season of the year in polar and temperate zones. This season occurs before spring and after autumn each year. </u></em>
  • <em><u>Winter temperatures are often below freezing. Since the winter is cooler, this encourages trees to shed their leaves. Trees and plants stop growing during this season.</u></em>
  • <em><u>Therefore, it is during winter season when forests would look very stark.</u></em>
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Where are the sun's rays the strongest, which makes the ocean water the warmest ?
IgorC [24]
The Gamma Rays are the strongest. This would be located near the core of the sun. What makes ocean water the warmest depends on the season we are in. This is all due to the energy input into the sun.
8 0
3 years ago
Four model rockets are launched in a field. The mass of each rocket and the
TiliK225 [7]

Answer: it is rocket 2

Explanation: I just took the test

Hope it's the right answer for you

4 0
4 years ago
If the work required to speed up a car from 11 km/h to 21 km/h is 6.0×103 J , what would be the work required to increase the ca
goblinko [34]

Explanation:

We need convert the velocities first to m/s and we get the following:

v2 = 21 km/hr = 5.8 m/s

v1 = 11 km/hr = 3.1 m/s

We need to find the mass of the car also for later use do using the work-energy theorem:

delta \: w =  \frac{1}{2} m(v \frac{2}{2}  - v\frac{2}{1} )

6.0x10^3 J = (0.5) m [(5.8)^2 - (3.1)^2]

or

m = 499.4 kg

Now we determine work needed delta W to change its velocity from 21 km/hr to 33 km/hr

v2 = 33 km/hr = 9.2 m/s

v1 = 21 km/hr = 5.8 m/s

delta W = (0.5)(499.4)[(9.2)^2 - (5.8)^2]

= 1.3 x 10^4 J

6 0
3 years ago
Two forces act on wooden box with mass of (30kg) (if F1,=85.7N east and F270.7N west):
tresset_1 [31]

The acceleration of the wooden box is 6.17 m/s² towards the west.

<h3 /><h3>What is acceleration?</h3>

Acceleration can be defined as the rate of change of velocity.

To calculate the acceleration of the wooden box can be calculated using the formula below.

Formula:

  • F₂-F₁ = ma.................. Equation 1

Where:

  • F₂ = Force on the wooden box acting towards west
  • F₁ = Force on the wooden box acting towards the east
  • m = Mass of the wooden box.
  • a = Acceleration of the wooden box

Make a the subject of the equation

  • a = (F₂-F₁)/m........................ Equation 2

From the question,

Given:

  • F₂ = 270.7 N
  • F₁ = 85.7 N
  • m = 30 kg

Substitute these values into equation 2

  • a = (270.7-85.7)/30
  • a = 185/30
  • a = 6.17 m/s² towards the west.

Hence, The acceleration of the wooden box is 6.17 m/s² towards the west.

Learn more about acceleration here: brainly.com/question/605631


7 0
2 years ago
Formula da força de atrito
pentagon [3]

F = μN

Explanation:

Choose the normal force acting between the object and the ground. Let's assume a normal force of 250 N .

Determine the friction coefficient. ...

Multiply these values by each other: (250 N) * 0.13 = 32.5 N .

You just found the force of friction.

3 0
3 years ago
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