Answer:
2.9 N
Explanation:
When the separation distance, r, is 0.5 m, the electrostatic force is 0.32 N. Electrostatic force is given as:
F = (k * q1 * q2) / r²
Where F = force acting on the balloons
k = Coulombs constant
Therefore:
0.32 = (k * q1 * q2) / 0.5²
=> k * q1 * q2 = 0.32 * 0.5² ------------(1)
When the distance is decreased by 3, that is r = r/3 = 0.5/3
F = (k * q1 * q2) / (0.5/3)² ------------(2)
Putting (1) into (2):
=> F = (0.32 * 0.5²) / (0.5/3)²
F = (0.32 * 0.5² * 3²) / 0.5²
F = 2.9 N
Therefore, the force would be 2.9 N
The initial force of motion and inward acting force
Answer:
Explanation:
Given that,
A point charge is placed between two charges
Q1 = 4 μC
Q2 = -1 μC
Distance between the two charges is 1m
We want to find the point when the electric field will be zero.
Electric field can be calculated using
E = kQ/r²
Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.
Then, the magnitude of the electric at point x is zero.
E = kQ1 / r² + kQ2 / r²
0 = kQ1 / x² - kQ2 / (1-x)²
kQ1 / x² = kQ2 / (1-x)²
Divide through by k
Q1 / x² = Q2 / (1-x)²
4μ / x² = 1μ / (1 - x)²
Divide through by μ
4 / x² = 1 / (1-x)²
Cross multiply
4(1-x)² = x²
4(1-2x+x²) = x²
4 - 8x + 4x² = x²
4x² - 8x + 4 - x² = 0
3x² - 8x + 4 = 0
Check attachment for solution of quadratic equation
We found that,
x = 2m or x = ⅔m
So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.
Answer:
From what I know they postponed the movies that were suppose to come out.
Which one looks like a screw
A is shoes
B is a fork (lever)
C is a wind chime shaped like a screw
D is a stapler (lever)