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fgiga [73]
3 years ago
12

Double standard refers to

Chemistry
1 answer:
Irina18 [472]3 years ago
3 0
A rule or principle that is unfairly applied in different ways to different people or groups
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How much solar radiation is reflected back by clouds?
inna [77]

Answer:

it's D

Explanation:

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6. Below is a table comparing atoms of different elements. Write your
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let me get my    glasses

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2 years ago
Let this be an easy 5 points to your brainly points all I ask is for you to answer with "thank you"
Sergio039 [100]

Answer:

1. Double displacement reaction

2. Trisodium phosphate and potassium hydroxide

3. Sodium hydroxide and Potassium phosphate

Explanation:

1)

The given chemical reaction is as follows.

Na_{3}PO_{4}+KOH\rightarrow NaOH+K_{3}PO_{4}

The balanced chemical reaction is as follows.

Na_{3}PO_{4}+3KOH\rightarrow 3NaOH+K_{3}PO_{4}

In the above reaction two reactants are exchange their cations. Therefore, it is a double displacement reaction.

2)

Na_{3}PO_{4}+3KOH\rightarrow 3NaOH+K_{3}PO_{4}

In the above reaction left side of the reaction is considered as reactants.

Na_{3}PO_{4} - Trisodium phosphate

KOH - Potassium hydroxide

3)

Na_{3}PO_{4}+3KOH\rightarrow 3NaOH+K_{3}PO_{4}

In the above reaction right side of the reaction is considered as products.

NaOH - Sodium hydroxide

K_{3}PO_{4} - Potassium phosphate.

4 0
3 years ago
Help me on the science please
Stells [14]
Reactants are on the left side of the arrow, while products are on the right
4 0
3 years ago
How much heat is required to change 56.0 g of ice (H2O) at 263 K to vapor (steam) at 400 K?
Leona [35]

Heat required = 173 kJ

<h3>Further explanation</h3>

Given

56.0 g of ice

Temperatur at 263 K(-10 C) to 400 K(127 C)

Required

Heat needed

Solution

1. raise the temperature(-10 C to 0 C)⇒c ice=2.09 J/g C

\tt Q=56\times 2.09\times (0-(-10)=1170.4~J

2. phase change (ice to water)⇒Heat of fusion water=334 J/g

\tt Q=56\times 334=18704~J

3. raise the temperature(0 C to 100 C)⇒c water= 4.18 J/g C

\tt Q=56\times 4.18\times (100-0)=23408~J

4. phase change(water to vapor)⇒heat of vaporization water=2260 J/g

\tt Q=56\times 2260=126560~J

5. raise the temperature(100 C to 127 C)⇒c vapor=2.09 J/g C

\tt Q=56\times 2.09\times (127-100)=3160.08~J

Total heat :

1170.4+18704+23408+126560+3160.08=173,002.48 J=173 kJ

7 0
3 years ago
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