Answer:
c. By itself, heme is not a good oxygen carrier. It must be part of a larger protein to prevent oxidation of the iron.
e. Both hemoglobin and myoglobin contain a prosthetic group called heme, which contains a central iron ( Fe ) (Fe) atom.
f. Hemoglobin is a heterotetramer, whereas myoglobin is a monomer. The heme prosthetic group is entirely buried within myoglobin.
Explanation:
The differences between hemoglobin and myoglobin are most important at the level of quaternary structure. Hemoglobin is a tetramer composed of two each of two types of closely related subunits, alpha and beta. Myoglobin is a monomer (so it doesn't have a quaternary structure at all). Myoglobin binds oxygen more tightly than does hemoglobin. This difference in binding energy reflects the movement of oxygen from the bloodstream to the cells, from hemoglobin to myoglobin.
Myoglobin binds oxygen
The binding of O 2 to myoglobin is a simple equilibrium reaction:
Answer:
The concentration of the copper sulfate solution is 83 mM.
Explanation:
The absorbance of a copper sulfate solution can be calculated using Beer-Lambert Law:
A = ε . c . <em>l</em>
where
ε is the extinction coefficient of copper sulfate (ε = 12 M⁻¹.cm⁻¹)
c is its molar concentration (what we are looking for)
l is the pathlength (0.50 cm)
We can use this expression to find the molarity of this solution:
Answer:
Groups 14, 15, and 16 have 2,3, and 4 electrons in the p sublevel (p sublevel has 3 "spaces" AKA orbitals), because Hunds says one in each orbital before doubling up if you had 2 electrons, group 14, they would both be in the first orbital, with 3 electrons, group 15, two in the first orbital one in the 2nd none in the 3rd. With 4 electrons, group 16, then you would have 2 in the first 2 orbitals and NONE in the 3rd.
Explanation:
If you are in group 13 you only have 1 electron so it can only be in one orbital. with group 17, you have 5 electrons, so 2 in the first 2 in the second and 1 in the 3rd, correct for Hunds rule anyway. Noble gasses, group 18, have 6 elecctrons, so every orbital is full any way you look at it.
Answer:
0.54g of Cr
Explanation:
Current (I) = 10A
Time (t) = 100s
Molecular mass of Cr = 51.996 amu
Faraday's first law of electrolysis states that
The mass of the substance (m) of a given substance deposited at an electrode is directly proportional to the quantity of electricity or charge (Q) passed
m = nQ
M = mass of the substance
n = electrochemical constant
Q = charge passed through it
Q = IT
Q = (10 * 100) = 1000C
1 moles = molarmass = Faraday's constant (96500C)
Molar mass = Faraday's constant (96500C)
51.996 g = 96500C
How many grams will be liberated with 1000C
51.996g = 96500C
Xg = 1000C
X = (1000 * 51.996) / 96500
X = 51996 / 96500
X = 0.5388g = 0.54 g of Cr will be deposited
