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4 years ago

When is the speed of light constant 299,792,458 meters per second? In air In water In any medium In a vacuum

Physics

2 answers:

wlad13 [49]4 years ago

8 0

Answer: In a vacuum

Explanation:

The speed of light in a vacuum is $299,792,458 m s$ but it is approximated to $3(10)^{8} m/s$ , and this value is a constant which has been denoted as $c$ .

However, in other media different from vacuum, the speed of light will depend on its molecular structure, specifically on its electromagnetic properties, its electrical permittivity and magnetic permeability.

In addition, it is important to note that in these materials or media different from vacuum, the speed of light will be less than $c$ and will depend on the medium's index of refraction.

Kazeer [188]4 years ago

7 0

Answer:

In a vacuum

Explanation:

I took the Test

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What does the variable p stand for in physics?

LUCKY_DIMON [66]

Is this a complete question or is there a problem to match it? maybe goggle it?

6 0

4 years ago

A circular loop of flexible iron wire has an initial circumference of 165.0cm, but its circumference is decreasing at a constant

djverab [1.8K]

Answer:

0.005 V

Explanation:

We are given that

Initial circumference of circular loop=C=165 cm

Rate of circumference, $\frac{dC}{dt}=12 cm/s$

Magnetic field,B=0.5 T

We have to find the induced emf at time t=9 s

We know that induced amf,E= $\frac{Bd(A)}{dt}$

Area of circular coil,A= $\pi r^2$

$E=B\frac{d(\pi r^2)}{dt}=B(2\pi r)\frac{dr}{dt}$

Circumference of circular coil,C= $2\pi r$

$165=2\pi r$

$r=\frac{165}{2\pi}$

$\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}\times (12)=\frac{6}{\pi} cm/s=\frac{6\times 10^{-2}}{\pi} m/s$

Radius of coil at time t=9 s

$r=\frac{165}{2\pi}-(\frac{6}{\pi}\times 9)=9.08 cm=9.08\times 10^{-2} m$

$1 m=100 cm$

E= $-0.5(2\pi\times 9.08\times 10^{-2})\times \frac{6\times 10^{-2}}{\pi}=-0.005 V$

Magnitude of induced emf=0.005 V

4 0

3 years ago

Read 2 more answers

A golfer, driving a golf ball off the tee, gives the ball a velocity of 38 m/sec. The mass of the ball is 0.045 kg, and the dura

atroni [7]

Answer:

$\Delta p=1.71\frac{kg\cdot m}{s}$

Explanation:

The momentum of a body is defined as the product of its mass and its velocity at a given time. Therefore the change in the momentum of the ball is given by the difference between the final momentum and the initial momentum:

$\Delta p=p_f-p_i\\\Delta p=mv_f-mv_i\\\Delta p=m(v_f-v_i)\\\Delta p=0.045kg(38\frac{m}{s}-0\frac{m}{s})\\\Delta p=1.71\frac{kg\cdot m}{s}$