All categories

3 years ago

A crane with output power of 200w lift a 600N object a vertical distance of 4 meters in how many seconds

Physics

1 answer:

bulgar [2K]3 years ago

3 0

1 w = 1N/s the change in total energy =mgh = 600*4 = 2400N. 2400N/200N/s = 12seconds

You might be interested in

Why is using fossil fuels considered unsustainable?

ikadub [295]

Answer:

Fossil fuels take millions of years to replenish

3 0

3 years ago

Read 2 more answers

What is the natural frequency (wo) of a circuit that has an inductor of 0.048 henery's, and a capacitor of 0.0004 farads?

adell [148]

Answer:

The natural frequency will be 228.11 rad/sec

Explanation:

We have given Inductance L = 0.048 Henry

And the capacitance C = 0.0004 farad

We have to find natural frequency

When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by $\omega _0=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.048\times 0.0004}}=228.21\ rad/sec$

So the natural frequency will be 228.21

4 0

2 years ago

Convert 68852 millijoules into Calories. (Write your answer in the decimal form. Do not include units in your answer).

alex41 [277]

Answer: 68852 millijoules = 16.46 calories

Explanation:

Given;

Convert 68852 millijoules to calories.

1 calorie = 4.184J = 4184millijoules

Therefore,

1 millijoule = 1/4184 calories

68852 millijoule = 68852 × 1/4184 calories

= 16.46 calories

6 0

3 years ago

which best describes what happens with the sonar to sound pulses from a ship after they hit the ocean floor?

lakkis [162]

Answer:

With sonar, what happens to sound pulses from a ship after they hit the ocean floor? ... They bounce back to the ship.

Explanation:

3 0

3 years ago

A frog leaps up from the ground and lands on a step 0.1 m above the ground 2 s later. We want to find the

mash [69]

Answer:

$\Delta x = v_0 t + \frac{1}{2}at^2$

Explanation:

To solve this problem, we can use the following suvat equation:

$\Delta x = v_0 t + \frac{1}{2}at^2$

where

$\Delta x$ is the vertical displacement of the frog

$v_0$ is the initial vertical velocity

t is the time

a is the acceleration

We have chosen this formula because apart from $v_0$ , all the other quantities are known. In fact:

$\Delta x =0.1 m$ is the vertical displacement

t = 2 s is the total time of flight

$a=g=-9.8 m/s^2$ is the acceleration due to gravity (negative because it is downward)

Therefore, solving for $v_0$ , we find the initial velocity of the frog:

$v_0 = \frac{\Delta x-\frac{1}{2}at^2}{t}=\frac{0.1-\frac{1}{2}(-9.8)(2)^2}{2}=9.85 m/s$

4 0

3 years ago