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2 years ago

Question 10 of 25

Chemistry

2 answers:

kap26 [50]2 years ago

7 0

Answer:

Correct option would be A. Mg(s) → Mg2+ + 2e-

Explanation:

Marked as correct answer on Quiz ;) (A P E X)

Julli [10]2 years ago

7 0

Answer:

A. Mg(s) → Mg2+ + 2e

Explanation:

it was correct lol

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2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.

ElenaW [278]

2:2 so the same proportion
0,03

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2 years ago

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Why is it important for someone to hold enzymes in their functional shapes

kumpel [21]

Answer:

there are spaces within the enzymes that is active. That active site allows substrates to join in. This helps the enzyme carry out the chemical reaction with the substrate.

Explanation:

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3 years ago

When neurotransmitter is released into the synaptic cleft, it is taken up by the post-synaptic neuron.

gogolik [260]

Answer:

Plz make me brainliest

Explanation:

The neurotransmitters released into the cleft diffuse through it to reach the post-synaptic neuron. Neurotransmitters remain in cleft for only some time. They are either taken up by the presynaptic neuron or are broken down by the enzymes present in the synaptic cleft. The post-synaptic neuron contains several receptors on its plasma membrane

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3 years ago

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

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2 years ago

Which equation is used to help form the combined gas law? mc009-1. Jpg mc009-2. Jpg mc009-3. Jpg mc009-4. Jpg.

Luba_88 [7]

The combined gas law equation has been $\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$ .

The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.

In an ideal gas the equation has been given as:

$PV=nRT$

Where, P has been the pressure of the gas

V has been the volume of the gas

n has been the moles of the gas

R has been a constant

T has been the temperature of the gas

The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

For more information about combined gas law, refer to the link:

brainly.com/question/13154969

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2 years ago