. For an elastic head-on (assumed) collision between equal masses, they simply swap velocities. The final velocities of objects 1 and 2 are 0 and v, respectively.
<span>2. mv = (2m)u </span>
<span>where u = final velocity. Then u = v1 = v2 = v/2 </span>
<span>3. Initially, p = (2m)v </span>
<span>final p = 2mv = 2mv1 + mv2 </span>
<span>But for an elastic head-on collision, we know that the </span>
<span>relative velocity of approach = relative velocity of separation, or </span>
<span>v = v2 - v1 </span>
<span>v2 = v + v1 </span>
<span>plug into final p: </span>
<span>2mv = 2mv1 + m(v + v1) = 2mv1 + mv + mv1 </span>
<span>mv = 3mv1 </span>
<span>v1 = v/3 </span>
<span>v2 = v + v/3 = 4v/3 </span>
<span>4. initial p = mv </span>
<span>final p = mv = (m + 3m)u = 4mu </span>
<span>u = v1 = v2 = v/4</span>
Answer:
Sound wave enters the outer ear and travels through a narrow passageway called the ear canel, which leads to the eardrums
Answer:
Notice that light from more distant objects takes a longer time to travel to Earth. Now continue to Part C to be sure you understand the implications for what we actually see in the night sky.
Explanation: