In what ways does energy transform or convert from one form to another?
1 answer:
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Answer:
P₂ = 1.22 kPa
Explanation:
This problem can be solved using the equation of state:
where,
P₁ = initial pressure = 1 KPa
P₂ = final pressure = ?
V₁ = initial Volume = 1 liter
V₂ = final volume = 1.1 liter
T₁ = initial temperature = 290 k
T₂ = final temperature = 390 k
Therefore,
<u>P₂ = 1.22 kPa</u>
<h2>Answer:</h2>
1.8 x 10⁻⁵J
<h2>Explanation:</h2>The energy (E) stored in a capacitor of capacitance, C, when a voltage, V, is supplied is given by;
E = x C x V² -------------------(i)
Now, from the question;
C = 2.00μF = 2.00 x 10⁻⁶F
V = 18.0V
Substitute these values into equation (i) as follows;
E = x 2.00 x 10⁻⁶ x 18.0
E = 1.8 x 10⁻⁵J
Therefore, the quantity of energy stored in the capacitor is 1.8 x 10⁻⁵J
To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.
The electric field is
Here,
= Linear charge density
= Permittivity of free space
r = Distance
The linear charge density can be written as,
Linear charge density is given as
Replacing,
The initial and final electric Force can be written as function of the charge and the electric field as
If we replace the value for the electric field we have,
Length is one third at the end, then
The ratio of the force is
Therefore the required ratio is 3