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masha68 [24]
2 years ago
12

PLEASE HELP ME I AM TIMED!

Physics
1 answer:
Arte-miy333 [17]2 years ago
6 0
The sequence of rock layers can be disturbed by erosion and earthquakes


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If you move 50 meters in 10 seconds, what is your speed ​
iogann1982 [59]

Explanation:

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8 0
2 years ago
If the moon is a full moon tonight what will be the moon one week later waxing or waning
tatiyna

-- Starting from nothing (New Moon), the moon's shape grows ('waxes')
for half of the cycle, until it's full, and then it shrinks ('wanes') for the next
half of the cycle.

-- The moon's complete cycle of phases runs 29.53 days . . . roughly
four weeks.

-- So, beginning from New Moon, it spends about two weeks waxing until
it's full, and then another two weeks waning until it's all gone again.
 
-- After a Full Moon, the moon is waning for the next two weeks.  So it's
definitely <em>waning</em> at <em><u>one week</u></em> after Full.


5 0
2 years ago
Which part of an object's rate of change best defines acceleration?
grandymaker [24]
I believe it is speed.

Hope this helps!
5 0
3 years ago
Read 2 more answers
A series RLC circuit has a resonant frequency = 6.00 kHz. When it is driven at a frequency = 8.00 kHz, it has an
ANEK [815]

The resistance (R) of the circuit is 707.1 ohms and the inductance (L) is 0.032 H.

<h3>Resistance of the circuit</h3>

For the phase constant of 45⁰, impedance is equal to the resistance of the circuit.

Z= R\sqrt{2} \\\\R  = \frac{Z}{\sqrt{2} } \\\\R = \frac{1000}{\sqrt{2} } = 707.1 \ ohms

<h3>Resonant frequency</h3>

f = \frac{1}{2\pi \sqrt{LC} } \\\\6000 = \frac{1}{2\pi \sqrt{LC} } \\\\2\pi(6000) = \frac{1}{\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi (6000)} \\\\LC = (\frac{1}{2\pi (6000)})^2\\\\LC = 7.034 \times 10^{-10} \\\\ C = \frac{7.034 \times 10^{-10} }{L} ---(1)

<h3>At driven frequency</h3>

X_l- X_c = R\\\\\omega L - \frac{1}{\omega C}  = 707.1\\\\2\pi f L -  \frac{1}{2\pi fC} = 707.1\\\\2\pi (8000) L - \frac{1}{2\pi (8000) C } = 707.1\ \ --(2)\\\\

<em>solve 1 and 2 together</em>

2\pi(8000) L - \frac{L}{2\pi (8000)(7.034 \times 10^{-10})} = 707.1\\\\50272L - 28279.48L = 707.1\\\\L = 0.032 \ H

Learn more about impedance of RLC circuit here: brainly.com/question/372577

7 0
2 years ago
Suppose that the hatch on the side of a Mars lander is built and tested on Earth so that the internal pressure just balances the
Kaylis [27]

Answer:

The value is  F_{net} =  4444 lb

The force will be  outward

Explanation:

From the question we are told that

   The diameter of the disk is  d = 50.0 \ cm  = \frac{50}{100} = 0.5 \ m

   The external pressure on Mars  is P = 650 \ N/m^2

From the question we are told that  

   Internal pressure  =  External pressure

Generally the external Force on earth is

      F_E = P_{atm} * A

Here P_{atm} is the atmospheric pressure with value  P_{atm} = 1.013*10^{5}\ Pa

So

      F_E = 1.013 *10^{5} * \pi * \frac{d^2}{4}

=>   F_E = 1.013 *10^{5} *3.142 * \frac{0.50 ^2}{4}

=>   F_E = 19893 \  N

Generally the external Force on Mars is  

       F= P * A

      F = 650 * \pi * \frac{d^2}{4}

=>   F = 650 *3.142 * \frac{0.5^2}{4}

=>   F = 127.6 \  N    

Net force is mathematically represented as

      F_{net} = F_E -F

=>    F_{net} =  19893  -127.6

=>    F_{net} =  19765.6 \ Nconverting to  pounds

    F_{net} = \frac{19765.6}{4.448}

=> F_{net} =  4444 lb

Given that that the value is positive then the force will be  outward

7 0
2 years ago
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