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Gnom [1K]
4 years ago
8

Question 10 of 10

Physics
1 answer:
Margaret [11]4 years ago
7 0

Answer: D. 5.0(10)^{-38} J

Explanation:

The energy E of an electromagmetic wave is given by:

E=\frac{hc}{\lambda}

Where:

h=6.626(10)^{-34}J.s is the Planck constant

c=3(10)^{8} m/s is the speed of light in vacuum

Then hc=1.99 (10)^{-25}Jm

\lambda=4.0(10)^{12} m is the wavelength

Solving:

E=\frac{1.99 (10)^{-25}Jm}{4.0(10)^{12} m}

E=5.0(10)^{-38} J

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It is the amount of work you have done in a certain amount of time. <span />
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3 years ago
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Determine the speed of sound in air at 300 K. Also determine the Mach number of an aircraft moving in the air at a velocity of 3
amm1812

Answer:

c_3_0_0_K=347.19m/s

M=0.864

Explanation:

The speed of sound in the air increases 0.6 m / s for every 1 ° C increase in temperature.  An approximate speed can be calculated using the following empirical formula:

c=331.5+0.6\vartheta

Where:

\vartheta=T-273.15K\\\\

A more exact equation, usually referred to as adiabatic velocity of sound, is given by the following formula:

c=\sqrt{k*R*T}

Where:

R= Gas\hspace{3}constant\hspace{3}of\hspace{3}air=0.287kJ/kg*K=287J/kg*K\\k=Specific\hspace{3}heat\hspace{3}ratio=1.4\\T=Temperature=300K

Hence:

c=\sqrt{(287)*(1.4)*(300)} =347.1887095\approx347.19m/s

Now, the Mach number at which an aircraft is flying can be calculated by:

M=\frac{u}{c}

Where:

u= Velocity\hspace{3}of\hspace{3}the\hspace{3}moving\hspace{3}aircraft\\c= Speed\hspace{3}of\hspace{3}sound\hspace{3}at\hspace{3}the\hspace{3}given \hspace{3}altitude

Therefore:

M=\frac{300}{347.19} =0.8640833984\approx0.864

5 0
4 years ago
What is the outcome of the Training and Exercise Planning Workshop (TEPW)?
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Answer / Explanation:

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3 years ago
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Explanation:

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4 years ago
A shark swims around his circular pool. What is the centripetal force of the 681kg shark if the pool has a diameter of 14m and i
blsea [12.9K]
<span>29 Newtons
   Centripetal force is modeled by the equation:
  F = MV^2/R where
 F = force
 M = Mass
 V = Velocity
 R = Radius

   I will assume the shark is swimming in a circle with a radius of 14 m / 2 = 7 m. The actual radius will be smaller, but I'll assume that the question is simply poorly worded. So we need to calculate the velocity of the shark. The circumference of the circle is pi*14m = 43.98229715 m. And since velocity is defined as distance over time, we have a velocity of 43.98229715 m / 80 s = 0.549778714 m/s.

   Now substitute the known values into the equation for centripetal force.
 F = MV^2/R
 F = 681 kg * ( 0.549778714 m/s)^2 / 7m
 F = 681 kg * 0.302256635 m^2/s^2 / 7m
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 F = 29.40525261 kg*m/s^2
 F = 29.40525261 N
   Rounding to 2 significant figures gives a force of 29 Newtons.</span>
5 0
4 years ago
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