Answer:
The distance of the first bright fringe is given as 
The distance of the second dark fringe from the central bright fringe is given as 
Explanation:
From the question we are told that
The slit separation distance is 
The distance of the slit from the screen is 
The wavelength is 
For constructive interference to occur the distance between the two slit is mathematically represented as

Where m is the order of the fringe which has a value of 1 for first bright fringe
Substituting values


For destructive interference to occur the distance between the two slit is mathematically represented as
![Y_D = [n + \frac{1}{2} ] \frac{\lambda D}{d}](https://tex.z-dn.net/?f=Y_D%20%20%3D%20%20%5Bn%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%20%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D)
m = 2
so the formula to get the dark fringe is 
Now substituting values
![Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}](https://tex.z-dn.net/?f=Y_D%20%3D%20%5B%201%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%20%2A%20%5Cfrac%7B633%20%2A10%5E%7B-9%7D%20%2A%203.23%20%7D%7B0.00115%7D)


The correct answer is B. <span>0.002010812m3. Good Luck! :)</span>
Answer:
3
Explanation:
The half-life of a radioactive isotope is the time it takes for the mass of the sample to halve.
This can be rewritten as follows:

where
m(t) is the mass of the sample at time t
m0 is the original mass of the sample
n is the number of half-lives that passed
We see that if we take n=3, the amount of original sample left is

So 3 (3 half-lives) is the correct answer.
the 2 main categories of nonmetals are REACTIVE NONMETALS an NOBLE GAS.
hope it helps
Answer: 18.9 m
Explanation:
i did the kinematic equation & found the answer.