c because a generator generates electricity with the use of another energy source like nuclear,solar,wind,fossil fuel,gasoline or in rare cases temperature

5 0

3 years ago

URGENT!!!!!!!<br><br> PLEASE HELP WITH THIS PHYSICS PROBLEM

Levart [38]

Explanation:

Let

$x_1$ = distance traveled while accelerating

$x_2$ = distance traveled while decelerating

The distance traveled while accelerating is given by

$x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2$

$\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2$

$\:\:\:\:\:= 1125\:\text{m}$

We need the velocity of the rocket after 30 seconds and we can calculate it as follows:

$v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}$

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

$v^2 = v_0^2 + 2ax_2$

$0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2$

Solving for $x_2,$ we get

$x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}$

$\:\:\:\:\:= 4327\:\text{m}$

Therefore, the total distance x is

$x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}$

$\:\:\:\:= 5452\:\text{m}$

3 0

3 years ago

Un vehiculo se desplaza con movimiento rectilio uniforme. Sabiendo que recorre 90 km en 3 horas. Averiguo la velocidad en m/s.

SashulF [63]

Answer:

Velocidad = 500 m/s

Explanation:

Dados los siguientes datos;

Distancia = 90 km

Tiempo = 3 horas

Conversión;

Por distancia:

1 kilómetro = 1000 metros

90 kilómetros = 90 * 1000 = 90,000 metros

Para el tiempo:

1 hora = 60 segundos

3 horas = 60 * 3 = 180 segundos

Para encontrar la velocidad en m/s;

Matemáticamente, la velocidad viene dada por la ecuación;

$Velocidad = \frac {distancia} {tiempo}$

Sustituyendo en la fórmula, tenemos;

Velocidad = 90000/180

Velocidad = 500 m/s

5 0

2 years ago

An iron railroad rail is 800 ft long when the temperature is 31°C. What is its length (in ft) when the temperature is −17°C?

natta225 [31]

Answer:

799.54 ft

Explanation:

Linear thermal expansion is:

ΔL = α L₀ ΔT

where ΔL is the change in length,

α is the linear thermal expansion coefficient,

L₀ is the original length,

and ΔT is the change in temperature.

Given:

α = 1.2×10⁻⁵ / °C

L₀ = 800 ft

ΔT = -17°C − 31°C = -48°C

Find: ΔL

ΔL = (1.2×10⁻⁵ / °C) (800 ft) (-48°C)

ΔL = -0.4608

Rounded to two significant figures, the change in length is -0.46 ft.

Therefore, the final length is approximately 800 ft − 0.46 ft = 799.54 ft.

7 0

3 years ago