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Oksi-84 [34.3K]
3 years ago
13

100 POINTS AND BRAINLIST FOR BEST ANSWER!

Physics
2 answers:
Arturiano [62]3 years ago
8 0

Answer:

C. Air moves from regions of high pressure to regions of low pressure.

Explanation:

The air from the regions of high pressure will hold onto that pressure. So, when it moves into the regions with low pressure it'll turn into wind.  

The greater the pressure, the stronger the wind and vise versa.

<em>Hope this helps!</em>

antiseptic1488 [7]3 years ago
7 0

Answer:

Air moves from regions of high pressure to regions of low pressure.

Explanation:

When airs moves horizontally from regions of high pressure to low pressure, it creates wind. If the difference between high and low pressure is greater, then it makes the wind faster.

Best of Luck!

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320 / 300

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Un tubo de acero de 40000 kilómetros forma un anillo que se ajusta bien a la circunferencia de la tierra. Imagine que las person
Darina [25.2K]

Answer:

82.76m

Explanation:

In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.

You use the formula for the circumference of the steel ring:

C=2\pi r    (1)

C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)

you solve for r in the equation (1):

r=\frac{C}{2\pi}=\frac{4*10^7m}{2\pi}=6,366,197.724m

Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:

L=Lo[1+\alpha \Delta T]         (2)

L: final length of the tube = ?

Lo: initial length of the tube = 4*10^7m

ΔT = change in the temperature of the steel tube = 1°C

α: thermal coefficient expansion of steel = 13*10^-6 /°C

You replace the values of the parameters in the equation (2):

L=(4*10^7m)(1+(13*10^{-6}/ \°C)(1\°C))=40,000,520m

With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:

r'=\frac{C}{2\pi}=\frac{40,000,520m}{2\pi}=6,366,280.484m

Finally, you compare both r and r' radius:

r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m

Hence, the distance to the ring from the ground is 82.76m

4 0
3 years ago
A rotating heavy wheel is used to store energy as kinetic energy. If it is designed to store 1.00 x 106 J of kinetic energy when
valkas [14]

We know, 1\ rpm = \dfrac{2\pi}{60} \ rad/s .

64\ rpm\ is = \dfrac{2\pi}{60}\times 64\ rad/s\\\\= \dfrac{32\pi}{15}\ rad/s

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Hence, this is the required solution.

8 0
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