Given: Mass m = 5.00 Kg; Height h = 12 m; Time t = 15 s
Required: Power P = ?
Formula: P = Fd/t = mgh/t
P = (5.0 Kg)(9.8 m/s²)(12 m)/15 s
P = 39.2 Kg.m²/s² or
P = 39.2 J
Answer:
Energy = .13 W / m^2 energy of incident energy
N = 3500 Watts / day power needed
N = 3500 Watts (3600 * 24 sec) = .0405 Watts/sec
The problem must mean that one needs 3.5 Kw-days
3.5 Kw-days = 3500 watts * 86400 sec = 3.02E8 joules
150 J/sec-m^2 * .13 = 19.5 J / sec-m^2 usable energy
In one day 19.5 J/sec-m^2 = 1.68E6 J/m^2 usable energy received
Area = 3.028E8 J / 1.68E6 J/m2 = 180 m^2
One would need 180 m^2 of solar panels
That's quite a lot of energy
A 1100 watt microwave oven uses 1.1 kW while running so 3.5 kW for 24 hours seems to be quite a lot.
Answer:
The force constant of the spring is 735 N/m.
Explanation:
It is given that,
Mass of fruit, m = 1500 g = 1.5 kg
Compression in the scale, x = 0.02 m
We need to find the force constant of the spring on the scale. The force acting on the scale is given by using Hooke's law. So,
Also, F = mg
k is force constant
So, the force constant of the spring is 735 N/m.
The object is in free fall when and only when it is being affected by gravity alone. It is not being influenced by a significant amount of air resistance will always be in free fall. F(net)/m = acceleration