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Phantasy [73]
3 years ago
12

Two pieces of silk have an electric charge after being rubbed on a piece of amber. What will happen when the two silk pieces are

brought close together?
A.They will repel one another

B.They will attract one another

C.They will transfer their electrons from one to the other

D.They will not affect one another
Physics
2 answers:
wlad13 [49]3 years ago
8 0
I think they will repel one another lmk if this is right
pishuonlain [190]3 years ago
3 0
When the silk is rubbed against the amber, the silk loses electrons to the amber making the silk positve charge and the amber have a negiitve charge.

when u put both positive charged pieces of silk near each other they will repel each other becasue they have the same charge

law of repulsion states that like charges repel

i have a test on this stuff tmrw good luck! xx
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An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/. To determine the depth of
leva [86]

Answer;

=32.15 meters

Explanation;

Use the formula  

s= ut+ 0.5 a (t)^2 to find out 's'  

where s= distance traveled  

u=initial velocity which is zero in this case  

t= time taken to travel 's' distance  

a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )  

Therefore;

S = 0.5 * 1.62 * 6.3 * 6.3

    = 32.1489 meters

Thus; the crater is 32.15 meters deep.

3 0
3 years ago
The y-component of the force F which a person exerts on the handle of the box wrench is known to be 86 lb. Determine the x-compo
emmainna [20.7K]

Answer:

x-component of force is  38.18 lb where as magnitude of Force is 93.16

Explanation:

Fy of the force F exerted on the handle of the box wrench = 86 lb

Considering the triangle in Fig 1

magnitude of perpendicular = P =  12

magnitude of base = B = 5

using Pythagoras theorem

                        H= \sqrt{P^{2} + B^{2}}

                 H= \sqrt{12^{2} + 5^{2}}

            H=13\\\implies cos \theta = \frac{5}{13} \\\implies sin \theta = \frac{12}{13}\\

y-component of force is given given as:

                              86 = Fsin\theta\\F = 86 (\frac{13}{12})\\F = 93.16 lb\\F_{x} =F cos \theta\\F_{x} = 93.16 (\frac{5}{13})\\F_{x} =38.18 lb.

5 0
3 years ago
g A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.4 A when an additional 2.2 Ω resistor
Mrrafil [7]

Answer:

R1 = 5.13 Ω

Explanation:

From Ohm's law,

V = IR............... Equation 1

Where V = Voltage, I = current, R = resistance.

From the question,

I = 2 A, R = R1

Substitute into equation 1

V = 2R1................ Equation 2

When a resistance of 2.2Ω is added in series with R1,

assuming the voltage source remain constant

R = 2.2+R1,  and I = 1.4 A

V = 1.4(2.2+R1)................. Equation 3

Substitute the value of V into equation 3

2R1 = 1.4(2.2+R1)

2R1 = 3.08+1.4R1

2R1-1.4R1 = 3.08

0.6R1 = 3.08

R1 = 3.08/0.6

R1 = 5.13 Ω

6 0
3 years ago
Is it possible for an object at rest to have forces acting upon it? Explain
daser333 [38]

Answer:

Yeah

Explanation:

I mean, how about gravity for example! When you draw a free-body diagram, you will almost always have to include gravity. How about normal force, or static friction? There are defintely forces at hand.

5 0
3 years ago
A boy weighing 50 kg is running at 2m/s. What is its kinetic energy? *<br> 10 points
pentagon [3]
The answer is 100.
The formula is KE = 1/2mv^2
Then you plug in 50 to the m
And 2 to the v . That’s how I got 100 .
Hope this helps
8 0
3 years ago
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