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Phantasy [73]
3 years ago
12

Two pieces of silk have an electric charge after being rubbed on a piece of amber. What will happen when the two silk pieces are

brought close together?
A.They will repel one another

B.They will attract one another

C.They will transfer their electrons from one to the other

D.They will not affect one another
Physics
2 answers:
wlad13 [49]3 years ago
8 0
I think they will repel one another lmk if this is right
pishuonlain [190]3 years ago
3 0
When the silk is rubbed against the amber, the silk loses electrons to the amber making the silk positve charge and the amber have a negiitve charge.

when u put both positive charged pieces of silk near each other they will repel each other becasue they have the same charge

law of repulsion states that like charges repel

i have a test on this stuff tmrw good luck! xx
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You have to use the specific heat equation. 

Q = cmΔT where Q is the energy, c is specific heat, m is mass, and ΔT is change in temp.

So we can substitute our variables into the equation.

30000J = (390g)(3.9J*g/C)ΔT

Solving for ΔT, we get:

30000J/[(390g)*(3.9J*g/C) = ΔT

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I'm assuming the temperature is C, since it was not specified.

Hope this helps!
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Zolol [24]

Answer:

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Explanation:

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A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista
slamgirl [31]

Answer:

Stay the same

Explanation:

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Initially, it is given by

C=\frac{\epsilon_0 A}{d}

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A is the area of the plates

d is the separation between the plates

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The potential difference across the capacitor is given by

V= \frac{Q}{C}

where

Q is the charge on the plates

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We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:

V' = 2 V

Now we can analyze the electric field between the plates of the capacitor, which is given by

E=\frac{V}{d}

we said that:

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therefore, the new electric field will be

E'=\frac{2V}{2d}=\frac{V}{d}=E

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F = qE

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4 0
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