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3 years ago

What happens to a path of a light ray parallel to the principal axis, after it passes through a converging

1 answer:

3 0

Answer: The ray that passes through the focal point on the way to the lens will refract and travel parallel to the principal axis. ... All three rays should intersect at exactly the same point.

Explanation: Once these incident rays strike the lens, refract them according to the three rules of refraction for converging lenses.

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Jonathan has six strings that are the same thickness and are all the same material. He cuts the strings to different lengths and

harkovskaia [24]

The shortest string will have the highest pitch.

7 0

3 years ago

Read 2 more answers

In figure 16-2 is the temperature of the material within the cylinder greatest during the intake stroke, compression stroke, pow

erastovalidia [21]

Technically, we have no way of knowing that without seeing Figure 16-2.
So the question should be reported for incomplete content. But I'm
going to take a wild stab at it anyway.

There's so much discussion of 'cylinder' and 'strokes' in the question,
I have a hunch that it's talking about the guts of a 4-stroke internal
combustion gasoline engine.

If I'm right, then the temperature of the material within the cylinder is
greatest right after the spark ignites it. At that instant, the material burns,
explodes, expands violently, and drives the piston down with its stiff shot
of pressure.

This is obviously happening because of the great, sudden increase in
temperature when the material ignites and explodes.

It hits the piston with pressure, which leads directly to the power stroke.

5 0

3 years ago

The cost of energy delivered to residences by electrical transmission varies from $0.070/kWh to $0.258/kWh throughout the United

tankabanditka [31]

Answer:

(a) $ 1.48

(b) $ 0.005

Explanation:

(a)

First, we calculate the energy consumed, by using following formula:

E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (40 W)(1 KW/1000 W) = 0.04 KW

t = Time Duration = (2 weeks)(7 days/week)(24 h/day) = 336 h

Therefore,

E = (0.04 KW)(336 h) = 13.44 KWh

Now, we calculate cost, by following formula:

Cost = (E)(Unit Price)

Cost = (13.44 KWh)($ 0.11/KWh)

Cost = $ 1.48

(b)

First, we calculate the energy consumed, by using following formula:

E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (970 W)(1 KW/1000 W) = 0.97 KW

t = Time Duration = (3 min)(1 h/60 min) = 0.05 h

Therefore,

E = (0.97 KW)(0.05 h) = 0.0485 KWh

Now, we calculate cost, by following formula:

Cost = (E)(Unit Price)

Cost = (0.0485 KWh)($ 0.11/KWh)

Cost = $ 0.005

(c)

First, we calculate the energy consumed, by using following formula:

E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (5.203 x 10³ W)(1 KW/1000 W) = 5.203 KW

t = Time Duration = (40 min)(1 h/60 min) = 0.67 h

Therefore,

E = (5.203 KW)(0.67 h) = 3.47 KWh

Now, we calculate cost, by following formula:

Cost = (E)(Unit Price)

Cost = (3.47 KWh)($ 0.11/KWh)

Cost = $ 0.38

8 0

3 years ago

A wave is traveling at a speed of 15 m/s and it's wavelength is 5 m. Calculate the waves frequency

Anvisha [2.4K]

Answer:

The frequency of this wave is $3\; \rm Hz$ .

Explanation:

The frequency $f$ of a wave is the number of wavelengths that this wave covers in unit time (typically a second.)

The wave in this question travels at $v = 15\; \rm m \cdot s^{-1}$ . In other words, this wave covers $15\; \rm m$ in unit time (a second.) How many wavelengths $\lambda$ would that $15\; \rm m\;$ correspond to?

The question states that the wavelength of this wave is $\lambda = 5\; \rm m$ . Therefore, there would be $15 / 5 = 3$ wavelengths in the $15\; \rm m$ span that this wave covered in the unit time of one second ( $1\; \rm s$ .) Hence, the frequency of this wave would be $3\; \rm s^{-1}$ (three per second,) which is equivalent to $3\; \rm Hz$ (three Hertzs.)

In general, the frequency $f$ of a wave with speed $v$ and wavelength $\lambda$ would be:

$\displaystyle f = \frac{v}{\lambda}$ .

For the wave in this question:

$\begin{aligned}f &= \frac{v}{\lambda} \\ &= \frac{15\; \rm m \cdot s^{-1}}{3\; \rm s} = 3\; \rm s^{-1} = 3\; \rm Hz\end{aligned}$ .

3 0

3 years ago

Describe how you can you use a graduated cylinder to measure the volume of an irregular object

svet-max [94.6K]

Answer:Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid. The liquid will tend to curve downward. This curve is called the meniscus. Always read the measurement at the bottom of the meniscus.

Explanation:

8 0

3 years ago