Un ejemplo de fuerza de fricción en fluidos

morpeh [17]

Answer:

I think its B

Explanation:

because "This means that when you rubbed the plastic comb along your hair, your hair resisted the movement of the comb and slowed it down. The friction between two surfaces can cause electrons to be transferred from one surface to the other."

3 0

3 years ago

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A pulled tablecloth exerts a frictional force of 0.6 n on a plate with a mass of 0.4 kg. what is the acceleration of the plate?

Ludmilka [50]

The formula for acceleration is a = F/m; Where: F = force; m = mass
Given: F = .6n; m = .4kg; a = ?
a = F/m
= .6/.4
= 1.5

Therefore, the acceleration of the plate is 1.5 m/s^2

6 0

3 years ago

The famous scientist Galileo Galilei did several experiments with sloping planes, which he rolled metal balls down so that he co

KatRina [158]

Hi there!

The answer would be B. the slope of the plane.

Changing the slope of the plane would show how fast the ball went when Galileo changed the steepness of the slope. If he didn’t change the slopes steepness he would have the same results each time.

Hope this helps !

5 0

3 years ago

Cole is riding a sled with initial speed of 5 m/s from west to east. the frictional force of 50 n exists due west. the mass of t

stepan [7]

We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
$F=ma$
where $F=-50 N$ is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
$a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2$

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
$a= \frac{v_f^2-v_i^2}{2d}$
where
$v_f=0$ is the final speed of the sled
$v_i=5 m/s$ is the initial speed
$d$ is the distance covered

By rearranging the equation, we find d:
$d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m$

3 0

3 years ago

A student was traveling to see his grandmother who lives 15 miles north oh his home he started from rest and maintained a pace o

N76 [4]

Explanation:

Given parameters:

Distance = 15miles north = 24140.2m

Initial velocity = 0m/s

Final velocity = 4m/s

Unknown:

Speed, velocity and acceleration = ?

Solution:

The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.

Speed = $\frac{distance }{time}$

The speed of the student is 4m/s

Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;

Velocity = $\frac{displacement}{time}$

The velocity of the student is 4m/s due north

Acceleration is the change in velocity with time;

To find the acceleration, we use

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

4² = 0² + 2x a x 24140.2

a = $\frac{16}{2 x 24140.2}$ = 0.00033m/s²

3 0

3 years ago