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san4es73 [151]
3 years ago
14

Which of the following is a correct comparison of a compact fluorescent lamp and incandescent light bulbs?

Physics
2 answers:
Alekssandra [29.7K]3 years ago
8 0
The correct answer is C.  

Hope I helped.  
user100 [1]3 years ago
6 0

Answer:

C

Explanation:

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A 50 kg object traveling at 100 m/s collides (perfectly elastic) with a 50 kg object initially at rest.
tino4ka555 [31]

Answer:

a

Explanation:

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3 years ago
1. The property of a material to absorb liquid like water is called
frez [133]

Answer:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

Explanation:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

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3 years ago
Current what can do work in an electric device
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It could help transport important information
5 0
3 years ago
6. several light bulbs are connected in series across a 115 v source
Natalka [10]

Explanation:

a) I = V / R

1.70 = 115 / R

R = 115 / 1.70

R = 67.647

R = 67.65 ohms

Therefore, equivalent resistance is 67.65 ohms

b) Equivalent resistance of circuit from above sum is 67.65 ohms

Given resistance of each bulb is 1.50 ohms

Number bulbs = Equivalent resistance / Resistance of each bulb

= 67.65 / 1.50

= 45

8 0
2 years ago
How is this formula ( Rt= r1 x r2 / r1 + r2) which is used to calculate total resistance of two parallel resistors found from th
Maru [420]

Explanation:

The total resistance used to calculate the total resistance of the two parallel resistor is given by :

R_t=\dfrac{r_1\times r_2}{r_1+r_2}

Taking reciprocal of the above equation.

\dfrac{1}{R_t}=\dfrac{r_1+r_2}{r_1\times r_2}

We can also write the above equation as :

\dfrac{1}{R_t}=\dfrac{r_1}{r_1\times r_2}+\dfrac{r_2}{r_1\times r_2}

On simplification of above equation,

\dfrac{1}{R_t}=\dfrac{1}{r_2}+\dfrac{1}{r_1}

or

\dfrac{1}{R_t}=\dfrac{1}{r_1}+\dfrac{1}{r_2}

Hence, proved.

4 0
3 years ago
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