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arsen [322]
3 years ago
7

According to gay-lussac’s law: select one:

Physics
2 answers:
DaniilM [7]3 years ago
8 0
Gay-Lussac's Law states
P1 / T1 = P2 / T2
So the answer is b

svlad2 [7]3 years ago
4 0

Answer

D

Explanation:

Just did the assignment.

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15 points. give me the method.
AveGali [126]

Answer:

\boxed{{160 \:  m(s)}^{ - 1} }

Explanation:

if \:the \:  frequencies \: are \to \\   f_{1} =  640Hz  \\ and \\f_{2}   = 480Hz \:  \\ but \:  \boxed{v = f \gamma }:   f =  \frac{v}{ \gamma } \\ if \:  \gamma_{1}  -  \gamma _{2}  = 1 =  \gamma  \\ f_{1}  - f_{2}  = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 =  \boxed{{160 \:  m(s)}^{ - 1} }

5 0
2 years ago
Four equal masses m are so small they can be treated as points, and they are equallyspaced along a long, stiff mass less wire. T
gavmur [86]

The moment of inertia of a point mass about an arbitrary point is given by:

I = mr²

I is the moment of inertia

m is the mass

r is the distance between the arbitrary point and the point mass

The center of mass of the system is located halfway between the 2 inner masses, therefore two masses lie ℓ/2 away from the center and the outer two masses lie 3ℓ/2 away from the center.

The total moment of inertia of the system is the sum of the moments of each mass, i.e.

I = ∑mr²

The moment of inertia of each of the two inner masses is

I = m(ℓ/2)² = mℓ²/4

The moment of inertia of each of the two outer masses is

I = m(3ℓ/2)² = 9mℓ²/4

The total moment of inertia of the system is

I = 2[mℓ²/4]+2[9mℓ²/4]

I = mℓ²/2+9mℓ²/2

I = 10mℓ²/2

I = 5mℓ²

4 0
3 years ago
Perform the operation of 147.02 / 0.338, and report the result with the proper number of significant figures
Ede4ka [16]

Answer:

434.97041

Explanation:

4 0
2 years ago
Why a body in uniform velocity is zero acceleration ?​
seropon [69]
Uniform velocity means no Net force and therefore no acceleration. Acceleration only happens when the velocity changes.
4 0
3 years ago
The mass of a string is 5.9 × 10-3 kg, and it is stretched so that the tension in it is 200 n. a transverse wave traveling on th
bagirrra123 [75]

The velocity of the wave on the string is given by

v=\sqrt{\frac{T}{\frac{m}{L}}}  \\  v=\sqrt{\frac{TL}{m}}

Solving the above equation,

v^2=\frac{TL}{m} \\  L=\frac{v^2m}{T}

The frequency of the wave f=300 and wave length is 0.76

The velocity is v=(300)(0.76)=228

Substituting numerical values,

L=\frac{228^2(0.0059)}{200}\\ T=1.534

The length of the string is 1.534 m

4 0
3 years ago
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