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3 years ago

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Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the Moon is increasing in radius at a rate of app

roximately 4.0 cm/yr. Assuming this to be a constant rate, how many years will pass before the radius of the Moon's orbit increases by 3.84x 10^7 m (10%)?

1 answer:

melomori [17]3 years ago

7 0

Answer:

967500000 years

Explanation:

The Speed at which the radius of the orbit of the Moon is increasing is 4 cm/yr

Converting to m

1 m = 100 cm

$1\ cm=\frac{1}{100}\ m$

$4\ cm\y=\frac{4}{100}=0.04\ m/yr$

The distance by which the radius increases is 3.84×10⁷ m

Time = Distance / Speed

$\text{Time}=\frac{3.87\times 10^7}{0.04}\\\Rightarrow \text{Time}=967500000\ yr$

967500000 years will pass before the radius of the orbit increases by 10%.

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Answer:

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We have given Wavelength of the light \lambda = 240 nm

According to plank's rule ,energy of light

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$E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV$

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$\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}$

$\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }$

$\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm$

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Answer:

(b) EAST

Explanation:

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Answer:

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$\rho=\frac{0.3534}{3.55\times 10^{-4}}$

$\rho=995.50\ kg.m^{-3}$

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$\rho_w=$ density of water

$s=\frac{995.5}{1000}$

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