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azamat
3 years ago
11

Mohs scale is used in describing which characteristic?

Physics
2 answers:
AleksandrR [38]3 years ago
7 0
Mohs scale of mineral hardness is a qualitative scale that characterizes the scratch resistance of various minerals with the ablity of harder material to scratch softer material
natali 33 [55]3 years ago
4 0

Answer: Mohs scale is used to describe hardness of a mineral

Explanation:

The Mohs scale of mineral hardness is a scale given by Friedrich Mohs to analyse hardness of various minerals by the ability of harder mineral to scratch softer mineral.

The scale ranges from 1 to 10 with scale of 10 given to the hardest substance that is diamond.

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A cheetah and a gazelle are grazing in the savannah. The gazelle is 275 meters away from the gazelle safe zone and the cheetah i
KATRIN_1 [288]

Answer:

1) Yes, the gazelle gets to safety

2) The speed with which the gazelle needs to run, to beat the cheater by 2 seconds is approximately 29.79 m/s

Explanation:

1) The distance of the gazelle, from the gazelle safe zone = 275 m

The distance of the cheetah from the gazelle = 455 m

The speed of the gazelle = 25 m/s

The speed of the cheetah = 65 m/s

Therefore, we have;

Let the time the gazelle reaches the safe zone = t, which gives;

t = 275 m/(25 m/s) = 11

t = 11 seconds

Let the time the cheetah reaches the gazelle = t₁, we have;

455 + 25 × t₁ = 65 × t₁

t₁ = 455/40 = 11.375

t₁ = 11.375 seconds

The gazelle reaches the gazelle safe zone before the cheetah reaches the gazelle

Therefore, the gazelle gets to safety

2) In order for the gazelle to beat the gazelle by 2 seconds, we have;

The time for the cheetah to reach the safe zone = (275 + 455)/65 = 11.23 seconds

Therefore, we have;

In order for the gazelle to beat the gazelle by 2 seconds the time the cheetah reaches the safe zone = 11.23 - 2 = 9.23 s

The speed of the gazelle is then 275/9.23 ≈ 29.79 m/s

6 0
3 years ago
A tennis ball of mass m=0.060 kg and speed v=25 m/s strikes a wall at a 45 angle and rebounds with the same velocity at 45°. Wha
Diano4ka-milaya [45]

To solve this problem we will apply the concepts related to the Impulse which can be defined as the product between mass and the total change in velocity. That is to say

p = m\Delta v

Here,

m = mass

\Delta v = Change in velocity

As we can see there are two types of velocity at the moment the object makes the impact,

the first would be the initial velocity perpendicular to the wall and the final velocity perpendicular to the wall.

That is to say,

v_i = vcos\theta

v_f = -v sin\theta

El angulo dado es de 45° y la velocidad de 25, por tanto

v_i = (25)cos(45) = 17.68m/s

v_f = -(25)sin(45) = -17.68m/s

The change of sign indicates a change in the direction of the object.

Therefore the impulse would be as

p = 0.060(-17.68-17.68)

p = -2.12kg \cdot m/s

The negative sign indicates that the pulse is in the opposite direction of the initial velocity.

3 0
3 years ago
A liquid thermometer can be used to test for fevers. When body temperature increases,
aleksandr82 [10.1K]

Answer:A

Explanation:

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5 0
4 years ago
Help sdsfdfdsasfsdfdsaf
WITCHER [35]

Answer:

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4 0
3 years ago
A two-liter bottle is one-fourth full of water and three-quarters full of air. The air in the bottle has a gage pressure of 340
Fantom [35]

Answer:

The value is     P_G  =  2.925 *10^{5} \  Pa

Explanation:

From the question we are told that

   The  volume of the bottle is  v  =  2 \  L  =  2 *  10^{-3} \  m^3

   The gauge pressure of the air is P_g  =  340 \  kPa  =  340 *10 ^{3}  \  Pa

   

Generally the volume of air before the bottle is turned upside down is  

      V_a  =  \frac{3}{4}  * V

       V_a  =  \frac{3}{4}  *  2 *10^{-3}

       V_a  =  0.0015 \  m^3 }

Generally the volume air when the bottle is turned upside-down is

      V_u  =  \frac{5}{6}  *  2 *10^{-3}

       V_u  =  0.00167 \  m^3

From the the mathematical relation of adiabatic process we have that

     P_g *  V_a^r  =  P_G *  V_u^r

Here r is a constant with  a value  r =  1.4

So

      340 *10 ^{3}  *  0.0015^{1.4}  =  P_G *  0.00167^{1.4}

        P_G  =  2.925 *10^{5} \  Pa

3 0
3 years ago
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