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san4es73 [151]
4 years ago
13

How should the answer be reported using the correct number of significant figures?

Chemistry
1 answer:
valentina_108 [34]4 years ago
5 0
What are the calculation like answer
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A trial of this decomposition experiment, using different quantities of reactants than those listed in the question above produc
Paul [167]

Answer : The volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of O_2 gas = (740-22.4) torr = 717.6 torr

P_2 = final pressure of O_2 gas at STP= 760 torr

V_1 = initial volume of O_2 gas = 280 mL

V_2 = final volume of O_2 gas at STP = ?

T_1 = initial temperature of O_2 gas = 25^oC=273+25=298K

T_2 = final temperature of O_2 gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}

V_2=242.2mL=0.2422L

Therefore, the volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

5 0
4 years ago
Recovery standards are a necessary tool for determining exactly how much of a particular analyte you are able to extract from a
Dafna11 [192]

Answer:

2.05mg Fe/ g sample

Explanation:

In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.

In the problem you recover 3.5mg Fe / 1.0101g sample: <em>3.465mg Fe / g sample. </em>As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:

3.465 / 4×100 = <em>86,6%</em>

As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:

1.7mg Fe / 0.9582g sample× (100/86.6) = <em>2.05mg Fe / g sample</em>

<em></em>

I hope it helps!

5 0
4 years ago
Express the following in regular notation:
dusya [7]
A because if you multiple it, you will be moving the decimal one time
8 0
4 years ago
How many isomers are there with the formula c3h4? include both structural and geometric isomers?
sleet_krkn [62]
There are three possible Isomers for Molecular Formula C₃H₄. Isomers are;

                                           1) Propyne

                                           2) Propa-1,2-diene

                                           3) Cyclopropene

Structures of all three isomers are given below.

There are no geometrical isomers for given molecular formula because geometrical isomers are formed in compounds containing double bond with at least two bulky groups at both sp² hybridized carbons. In given isomers, propyne does not contain any double bond, Propa-1,2-diene is symmetrical in nature while cyclopropene is a 3-membered ring. And for cycloalkenes there must be other groups attached to ring other than Hydrogen atom, hence cyclopropene does not contain any other group, so it can not show geometrical isomerism.

7 0
3 years ago
List the 4 main components of air in their molecular form.
ICE Princess25 [194]

Answer:

Air is made up of 78.09% nitrogen, 20.95% oxygen, 0.93% argon, 0.04% carbon dioxide, and other gases in meager amounts.

3 0
3 years ago
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