1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marysya12 [62]
3 years ago
5

What can Lisa do to increase the strength of the electromagnet?

Physics
1 answer:
drek231 [11]3 years ago
4 0

Answer:

move the wire loops closer

Explanation:

because the closer t they are the more concentrated the energy is in that specific area

You might be interested in
In a model of the solar system that was about as large as a college campus how large would the Sun be?
nordsb [41]
Small car is the answer
8 0
2 years ago
The soccer game begins with a ______ ______ in the center of the field
blagie [28]
It begins with a kick-off
6 0
3 years ago
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro
svetoff [14.1K]

Answer:

The equation of motion is x(t)=-\frac{1}{3} cos4\sqrt{6t}

Explanation:

Lets calculate

The weight attached to the spring is 24 pounds

Acceleration due to gravity is 32ft/s^2

Assume x , is spring stretched length is ,4 inches

Converting the length inches into feet x=\frac{4}{12} =\frac{1}{3}feet

The weight (W=mg) is balanced by restoring force ks at equilibrium position

mg=kx

W=kx ⇒ k=\frac{W}{x}

The spring constant , k=\frac{24}{1/3}

                            = 72

If the mass is displaced from its equilibrium position by an amount x, then the differential equation is

    m\frac{d^2x}{dt} +kx=0

    \frac{3}{4} \frac{d^2x}{dt} +72x=0

  \frac{d^2x}{dt} +96x=0

Auxiliary equation is, m^2+96=0

                                 m=\sqrt{-96}

                               =\frac{+}{} i4\sqrt{6}

Thus , the solution is x(t)=c_1cos4\sqrt{6t}+c_2sin4\sqrt{6t}

                                 x'(t)=-4\sqrt{6c_1} sin4\sqrt{6t}+c_2  4\sqrt{6} cos4\sqrt{6t}

The mass is released from the rest x'(0) = 0

                    =-4\sqrt{6c_1} sin4\sqrt{6(0)}+c_2 4\sqrt{6} cos4\sqrt{6(0)} =0

                                                    c_2 4\sqrt{6} =0

                                     c_2=0

Therefore , x(t)=c_1 cos 4\sqrt{6t}

Since , the mass is released from the rest from 4 inches

                    x(0)= -4 inches

c_1 cos 4\sqrt{6(0)} =-\frac{4}{12} feet

   c_1=-\frac{1}{3} feet

Therefore , the equation of motion is  -\frac{1}{3} cos4\sqrt{6t}

7 0
2 years ago
A Honda Civic Hybrid weighs about 3200 lb .
Usimov [2.4K]
3200÷0.22= 145.4545...N
(it is an infinite decimal)
3 0
3 years ago
Read 2 more answers
what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?​
Reil [10]

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

3 0
3 years ago
Read 2 more answers
Other questions:
  • Two different sub-atomic particles are described below: Particle Y: Carries a positive charge Particle Z: Orbits the nucleus Whi
    15·2 answers
  • In which situation will the friction between an object and the surface on which it is moving be decreased? a. the object is push
    10·1 answer
  • A 616 g block is released from rest at height h0 above a vertical spring with spring constant k = 540 n/m and negligible mass. t
    14·1 answer
  • A 1.0 kg mass is attached to the end of a vertical ideal spring with a force constant of 400 N/m. The mass is set in simple harm
    8·1 answer
  • A 0.410 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 35.0 pC charge on it
    5·1 answer
  • Which phenomena support only the particle theory of light? Check all that apply.
    10·1 answer
  • A 2800 kg speedboat starting from rest attains a speed of 16 m/s in 8.0 s as a combination of 1200 N of air resistance and water
    8·1 answer
  • How much power is required to do 180 J of work in 2.4s?​
    13·2 answers
  • Answer (soon please)
    8·1 answer
  • A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!