Answer: a) vcar= 7 m/s ; b) a train= 0.65 m/s^2
Explanation: By using the kinematic equation for the car and the train we can determine the above values of the car velocity and the acceletarion of the train, respectively.
We have for the car
distance = v car* t, considering the length of train (81.1 m) travel by the car during the first 11.6 s
the v car = distance/time= 81.1 m/11.6s= 7 m/s
In order to calculate the acceleration we have to use the kinematic equation for the train from the rest
distance train = (a* t^2)/2
distance train : distance travel by the car at constant speed
so distance train= (vcar*36.35)m=421 m
the a traiin= (2* 421 m)/(36s)^2=0.65 m/s^2
I believe that the answer is C<span />
Answer:
In a concave mirror, if an object is located between the center of curvature and the focal point, what is the best way to describe the image formed? Real, inverted, and smaller than the object. Real, inverted, and larger than the object. light rays travel parallel to each other, no other image is formed.
1,000 grams = 1 kilogram
so 55 megagrams = 55,000 kilograms
100 cm = 1 meter
so 500 cm = 5 meters
Acceleration of gravity on Earth = 9.8 m/s²
Weight = (mass) x (gravity)
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Work = increase in potential energy =
(weight) x (height) =
(mass) x (gravity) x (height) =
(55,000 kg) x (9.8 m/s²) x (5 m) =
2,695,000 joules .