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tangare [24]
3 years ago
12

An eletric pump in the ground floor

Physics
1 answer:
ELEN [110]3 years ago
6 0

Answer:

The input power is 44.4\times10^{3}\ kW

Explanation:

Given that,

Time = 15 min

Volume of water = 30 m³

Height = 40 m

Efficiency = 30%

Density of water = 1000 kg/m³

Suppose, acceleration due to gravity = 10 m/s²

We need to calculate the mass of water pumped

Using formula of mass

Mass = Volume\times density

Put the value into the formula

Mass=30\times1000

Mass=3\times10^{4}\ kg

We need to calculate the output power

Using formula of power

P_{out}=\dfrac{W}{t}

P_{out}=\dfrac{mgh}{t}

Put the value into the formula

P_{out}=\dfrac{3\times10^{4}\times10\times40}{15\times60}

P_{out}=\dfrac{4}{3}\times10^{4}\ Watt

We need to calculate the input power

Using formula of efficiency

\eta=\dfrac{P_{out}}{P_{in}}

P_{in}=\dfrac{P_{out}}{\eta}

Put the value into the formula

P_{in}=\dfrac{4\times100\times10^{4}}{3\times30}

P_{in}=\dfrac{4\times10^{5}}{9}\ Watt

P_{in}=44.4\times10^{3}\ kW

Hence, The input power is 44.4\times10^{3}\ kW

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<h3>Work done by the applied force</h3>

The area under force versus displacement graph is work done.

The total work done by pulling the object 7 m, can be grouped into two areas;

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