All categories

3 years ago

An eletric pump in the ground floor

Physics

1 answer:

ELEN [110]3 years ago

6 0

Answer:

The input power is $44.4\times10^{3}\ kW$

Explanation:

Given that,

Time = 15 min

Volume of water = 30 m³

Height = 40 m

Efficiency = 30%

Density of water = 1000 kg/m³

Suppose, acceleration due to gravity = 10 m/s²

We need to calculate the mass of water pumped

Using formula of mass

$Mass = Volume\times density$

Put the value into the formula

$Mass=30\times1000$

$Mass=3\times10^{4}\ kg$

We need to calculate the output power

Using formula of power

$P_{out}=\dfrac{W}{t}$

$P_{out}=\dfrac{mgh}{t}$

Put the value into the formula

$P_{out}=\dfrac{3\times10^{4}\times10\times40}{15\times60}$

$P_{out}=\dfrac{4}{3}\times10^{4}\ Watt$

We need to calculate the input power

Using formula of efficiency

$\eta=\dfrac{P_{out}}{P_{in}}$

$P_{in}=\dfrac{P_{out}}{\eta}$

Put the value into the formula

$P_{in}=\dfrac{4\times100\times10^{4}}{3\times30}$

$P_{in}=\dfrac{4\times10^{5}}{9}\ Watt$

$P_{in}=44.4\times10^{3}\ kW$

Hence, The input power is $44.4\times10^{3}\ kW$

You might be interested in

Balance the following chemical equations

IrinaVladis [17]

Answer:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

Always use the upper case for the first character in the element name and the lower case for the second character.

To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}. Example: Fe{3+} + I{-} =...

Substitute immutable groups in chemical compounds to avoid ambiguity. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2...

Explanation:

4 0

4 years ago

Mars had a mass of 6.38* 10^23 kg and a radius of 3,390,000meter what is the force of gravity experienced by a mars rover with a

d1i1m1o1n [39]

I hope its helps you . you can also write 1.44×10^3 it will be better

7 0

2 years ago

cample 3.3 Calculate the number of moles for the following: (i) 52 g of He (finding mole from mass) i) x 12.044 x 1023 number of

Pavel [41]

Answer:

12.96 is the answer of these

3 0

3 years ago

Read 2 more answers

If the average velocity during the athlete's walk back

goblinko [34]

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

$T=\frac{d}{1.50}$

From the question we are told

If the average velocity during the athlete's walk back to the starting line in Guided Example 2.5 is – 1.50 m/s,

Generally the equation Time spent is mathematically given as

T=\frac{d}{v}

Therefore

$T=\frac{d}{1.50}$

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

$T=\frac{d}{1.50}$

For more information on this visit

brainly.com/question/22271063

4 0

3 years ago

Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb

Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

And we know that the equation for the radial acceleration is:

ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

w = 2*pi*f

where f is the frequency, and:

T = 1/f.

Then we can write:

w = 2*pi/T

and our equation becomes:

ar = r*(2*pi/T)^2

Now we solve this for r.

First we need to use the same units in both equations, so we want to write T in seconds.

T = 88 days,

A day has 24 hours, and one hour has 3600 seconds:

T = 88*24*3600 s =7,603,200s

Then:

3.96x10^-2 m/s^2 = r*(2*3.14/7,603,200s)^2

r = (3.96x10^-2 m/s^2) /(2*3.14/7,603,200s)^2 = 58,045,522,878.8 meters

5 0

3 years ago