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3 years ago

15

While studying gravity and acceleration, students record their lab journal that they believe two objects of different masses dro

pped from the same height will hit the ground at the dame time. The students have formulated a ?

1 answer:

timurjin [86]3 years ago

5 0

They've formulated a hypothesis.

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In a nuclear power plant control rods are used to

evablogger [386]

Control rods are used<span> in </span>nuclear<span> reactors to </span>control<span> the fission rate of uranium and plutonium. They are composed of chemical elements such as boron, silver, indium and cadmium that are capable of absorbing many neutrons without themselves fissioning.</span>

4 0

3 years ago

An aqueous solution of sucrose (C12H22O11C12H22O11) is prepared by dissolving 7.6330 gg in sufficient deionized water to form a

Mariana [72]

Answer:

The answer to your question is 0.64 M

Explanation:

Data

Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g

volume = 25 ml

Molarity = ?

Process

1.- Calculate the molar weight of Sucrose

C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)

= 144 + 22 + 176

= 342 g

2.- Calculate the moles of sucrose

342 g ------------------ 1 mol

7.633 g --------------- x

x = (7.633 x 1) / 342

x = 0.0223 moles

3.- Calculate the molarity

Molarity = moles / volume (L)

Molarity = 0.0223 / 0.035

Molarity = 0.64

6 0

3 years ago

What kind of simple machine is a shovel

Minchanka [31]

I think a shovel is a wedge simple machine.

8 0

2 years ago

Read 2 more answers

Consider the heating curve. In which region are most particles moving the fastest?

Nikitich [7]

The particles are moving fastest in Region D) 5.

As temperature increases, so does the average kinetic energy (speed) of the molecules.

5 0

2 years ago

Read 2 more answers

You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q

kicyunya [14]

Answer:

3,78 mL of 12,0wt% H₂SO₄

Explanation:

The equilibrium in water is:

H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)

The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = $10^{-7,2}$

Thus, you need to add:

[H⁺] = $10^{-7,2} - 10^{-8}$ = <em>5,31x10⁻⁸ M</em>

The total volume of the pool is:

7,00 m × 18,0 m ×1,50 m = 189 m³ ≡ 189000 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 189000 L = 1,00<em>x10⁻² moles of H⁺</em>

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,00x10⁻² moles of H⁺ × $\frac{1 H_{2}SO_{4} moles}{2H^+ mole}$ = <em>5,00x10⁻³ moles of H₂SO₄</em>

These moles comes from:

5,00x10⁻³ moles of H₂SO₄ × $\frac{98,1g}{1mol}$ × $\frac{100 gsolution}{12 g H_{2}SO_{4} }$ × $\frac{1mL}{1,080 g}$ = <em>3,78 mL of 12,0wt% H₂SO₄</em>

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I hope it helps!

5 0

3 years ago