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4 years ago

What force causes weight? How is weight affected as an object moves farther away from the center of the earth?

2 answers:

6 0

"What force causes weight?"
--Weight is caused by gravity. The weight of an object is determined between the gravitational force of the object and the Earth.

"How is weight affected as an object moves farther away from the center of the Earth?"
--As you travel away from the Earth's surface, your mass stays the same but your weight reduces as gravitational pull decreases.

stich3 [128]4 years ago

3 0

Gravity affects weight of an object

Its weight reduces as it moves away from the center as gravity is strongest near the core and reduces as you move away

Hope this helps C:

You might be interested in

You can follow the flow of energy in an ecosystem by following its food _____ or _____.

timofeeve [1]

You can follow the flow of energy in an ecosystem by following its food Chain or food web.

In short, Answers are:
1- Chain
2- Web

Hope this helps!

7 0

4 years ago

Read 2 more answers

You are driving your car on a very cold late Fall day. You clear a turn and see a couple of pedestrians standing at the cross wa

Diano4ka-milaya [45]

Answer:

t_pass = 2.34 m

t_stop = 4.68 s

Thus, for the car passing at constant speed the pedestrian will have to wait less.

Explanation:

If the car is moving with constant speed, then the time taken by it will be given as:

$t_{pass} = \frac{D}{v}$

where,

t_pass = time taken = ?

D = Distance covered = 23 m

v = constant speed = (22 mi/h)(1609.34 m/1 mi)(1 h/3600 s) = 9.84 m/s

Therefore,

$t_{pass} = \frac{23\ m}{9.84\ m/s} \\$

t_pass = 2.34 m

Now, for the time to stop the car, we will use third equation of motion to get the acceleration first:

$2as = v_{f}^{2} - v_{i}^2\\a = \frac{v_{f}^{2} - v_{i}^2}{2D}\\\\a = \frac{(0\ m/s)^{2}-(9.84\ m/s)^2}{(2)(23\ m)}\\\\a = -2.1\ m/s^2$

Now, for the passing time we use first equation of motion:

$v_{f} = v_{i} + at_{stop}\\t_{stop} = \frac{v_{f}-v_{i}}{a}\\\\t_{stop} = \frac{0\ m/s - 9.84\ m/s}{-2.1\ m/s^2}$

t_stop = 4.68 s

7 0

3 years ago

FIGURE 4.1 shows a rectangular wire loop 0.3 m x 0.2 m moving horizontally to the right at 12 ms -1 in a uniform magnetic field

timama [110]

<h3>Given :- </h3>

Length of the rectangular wire, L=0.3 m
Width of the rectangular wire, b=0.2m
Magnetic field strength, B=0.8 T
Velocity of the loop, v =12 m/s
Induced Current, I = 3 A

$\underline{\underline{\large\bf{Solution:-}}}\\$

(I) Emf developed,E in the loop is given as:

$\begin{gathered}\\\implies\quad \sf E = BLv \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf E = 0.8 \times 0.3 \times 12 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf E = 2.88 V \\\end{gathered}$

$\longrightarrow$ I = E/R

$\quad$ R = E/I

where

R = resistance
E = Induced EMF
I = Current

$\begin{gathered}\\\implies\quad \sf R = \frac{2.88}{3} \\\end{gathered}$

$\begin{gathered}\\\implies\quad \boxed{\sf{ R = 0.96 \;ohm}}\\\end{gathered}$

(ii) The direction of current induced is from P to Q which is given by B × V vector . It may also be explained by Lenz law. Since magnetic field is from S to N . The fingers of the right hand are placed around the wire so that the curling of fingers will show the direction of the magnetic field produced by the wire then the thumb points in the direction of current flow which is from P to Q.

3 0

2 years ago

Just how strong is the electric force? suppose you had two small boxes, each containing 1.0 g of protons. (a) if one were placed

vlabodo [156]

Let's use Newton's Law of Second Motion: F=ma. When no other direct force is acting on the system, the acceleration is due to the gravity. The modified equation becomes: F = mg. So, yes, you need to take into account the gravitational accelerations in the moon and on Earth.

g,moon = 1.622 m/s²
g,Earth = 9.81 m/s²

The net force is the tension of the string:

F,Earth - F,moon = Tension
Tension = (1/1000 kg)(9.81 m/s²) - (1/1000 kg)(1.622 m/s²)
Tension = 8.188×10⁻³ N

To convert, 1 pound force is equal to 4.45 Newtons:

Tension = 8.188×10⁻³ N * 1 lbf/4.45 N
Tension = 1.84×10⁻³ lbf

3 0

3 years ago

A boat has a velocity of 5m/s North with respect to a river. It aims to reach point A, directly north across the river, which is

Juli2301 [7.4K]

What are the answer

Need the answers

6 0

3 years ago