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Elden [556K]
3 years ago
6

A 100 N box sits on a 30 degree incline. If the static coefficient of friction is 0.1, what is the magnitude of the static frict

ional force acting on the box? Select one: a. 5.0 N
b. 8.7 N
c. 10N

Physics
1 answer:
Semmy [17]3 years ago
8 0

Answer:

f = 8.7 N                        

Explanation:

It is given that,

Weight of the box, W = 100 N

It is inclined at an angle of 30 degrees.

The coefficient of friction, \mu_s=0.1

We need to find the magnitude of the static frictional force acting on the box. Let f is the frictional force. It is given by :

f=\mu_s\times N

N is the normal force

f=\mu_s\times mg\ cos\theta  

f=0.1\times 100\times \ cos(30)  

f = 8.66 N

or

f = 8.7 N

So, the the static frictional force acting on the box is 8.7 N. Hence, this is the required solution.

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Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
butalik [34]

Answer:

a) I = -2257.6 Kg*m/s

b) F = -451,520N

Explanation:

part a.

we know that:

I = P_f-P_i

where I is the impulse, P_f the final momentum and P_i the initial momentum.

so:

I = MV_f-MV_i

where M is the mass, V_f the final velocity and V_i the initial velocity.

Therefore, we have to find the initial velocity or the velocity of the passenger just before the collition.

now, we will use the law of the conservation of energy:

E_i=E_f

so:

mgh = \frac{1}{2}MV_i^2

where g is the gravity and h the altitude. So, replacing values, we get:

(85kg)(9.8m/s^2)(36m)= \frac{1}{2}(85kg)V_i^2

solving for V_i:

V_i = 26.56m/s

Then, replacing in the initial equation:

I = MV_f-MV_i

I = (85kg)(0m/s)-(85kg)(26.56m/s)

I = -2257.6 Kg*m/s

Then, the impulse is -2257.6 Kg*m/s, it is negative because it is upwards.

part b.

we know that:

Ft = I

where F is the average force, t is the time and I is the impulse. So, replacing values, we get:

F(0,005s) = -2257.6 Kg*m/s

solving for F:

F = -451520N

Finally, the force is -451,520N, it is negative because it is upwards.

3 0
3 years ago
Please help
Andre45 [30]

Answer:

your

answer is

12.004

7 0
3 years ago
Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
gtnhenbr [62]

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒  \frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}

On substituting the values, we get

⇒  \frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}

On taking L.C.M, we get

⇒  \frac{1}{R_{net}} =\frac{2+1}{6}

⇒  \frac{1}{R_{net}} =\frac{3}{6}

⇒  \frac{1}{R_{net}} =\frac{1}{2}

On applying cross-multiplication, we get

⇒ R_{net}=2 \Omega

3 0
2 years ago
Are photons causing the electrons to flow off of the target? ( the target is calcium)
Sliva [168]

Answer:

The energy lost by the atoms is given off as an electromagnetic wave. ... even if it's not very intense, will always cause electrons to be emitted.

Explanation:

5 0
3 years ago
If it takes 726 watts of power to move a mass 36 meters in 14 seconds, then what is the magnitude of the object’s mass?
Colt1911 [192]

Answer:

20.2

Explanation: Divide 726/34 and you get 20.16 round it and you get 20.2

4 0
2 years ago
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