1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna71 [15]
4 years ago
13

The top of the cylinder head is sealed by the

Physics
2 answers:
zepelin [54]4 years ago
6 0

Answer:

Valve Cover

Explanation:

I've taken test

svetlana [45]4 years ago
3 0
The common name is valve cover, so the correct answer is A.
You might be interested in
How many minutes would it take a light wave to travel from the planet Venus to Earth? (Average distance from Venus to Earth = 28
Gnesinka [82]

Answer:

t=2.51min

Explanation:

The time taken by the light to travel a given distance is defined as:

t=\frac{d}{c}

Here c is obviously the speed of light. Now we convert the average distance form Venus to Earth to meters:

28*10^{6}mi*\frac{1609.34}{1mi}=4.51*10^{10}m

Finally, we calculate the minutes taken by the light to travel from Venus to Earth:

t=\frac{4.51*10^{10}m}{3*10^8\frac{m}{s}}\\t=150.33s*\frac{1min}{60s}=2.51min

6 0
4 years ago
A solenoid used to produce magnetic fields for research purposes is 2.1 m long, with an inner radius of 28 cm and 1000 turns of
Veseljchak [2.6K]

Answer:

I = 2172.46 A

Explanation:

Given that,

The length of a solenoid, l = 2.1 m

The inner radius of the solenoid, r = 28 cm = 0.28 m

The number of turns in the wire, N = 1000

The magnetic field in the solenoid, B = 1.3 T

We need to find the current carried by it. We know that, the magnetic field in a solenoid is given by :

B=\mu_o nI\\\\or\\\\B=\mu_o \dfrac{N}{L}I\\\\I=\dfrac{BL}{\mu_o N}

Put all the values,

I=\dfrac{1.3\times 2.1}{4\pi \times 10^{-7}\times 1000}\\\\I=2172.46\ A

So, it carry current of 2172.46 A.

7 0
3 years ago
What name is used for a high-power variable resistor?
const2013 [10]
The answer would be C: Rheostat.  :)
3 0
3 years ago
Read 2 more answers
Which of the following scientists taught physics in the United States?
Sergio039 [100]
<span>Subrahmanyan Chandrasekhar

</span>
6 0
3 years ago
Read 2 more answers
A rocket passes you at a speed of 0.85c, and you measure its length to be 35.0 m. What is its measured length when at rest?
viktelen [127]

Answer:

66.4 m

Explanation:

To solve the problem, we can use the length contraction formula, which states that the length observed in the reference frame moving with the object (the rocket) is given by

L=L_0 \sqrt{1-(\frac{v}{c})^2}

where

L_0 is the proper length (the length measured from an observer at rest)

v is the speed of the object (the rocket)

c is the speed of light

Here we know

v = 0.85c

L = 35.0 m

So we can re-arrange the equation to find the length of the rocket at rest:

L_0 = \frac{L}{\sqrt{1-(\frac{v}{c})^2}}=\frac{35.0}{\sqrt{1-(\frac{0.85c}{c})^2}}=66.4 m

8 0
4 years ago
Other questions:
  • The following is a chemical reaction for _______ with ozone.
    11·2 answers
  • Three-dimensional ____ programs allow designers to rotate designs of 3-d objects to view them from any angle.
    5·1 answer
  • The principal limitation of wind power is unpredictability. Please select the best answer from the choices provided
    13·2 answers
  • Juan is standing on the street. An ambulance moves toward him and then passes by. What best describes the pitch that Juan heats?
    8·1 answer
  • A postman needs to deliver a parcel to Peter's house 5
    11·1 answer
  • PLS ANSWER FAST WILL GIVE BRAINLY!!!<br><br><br> How can you know if something has energy?
    7·1 answer
  • 1. Faça as transformações:
    5·1 answer
  • Camera lenses are described in terms of
    15·1 answer
  • A runner slows down after completing works her deceleration is 0.25m/s after 5 sec she is traveling at 4m/s determine her initia
    10·1 answer
  • List the two things that affect gravitational force.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!