Answer:
a. d₁/d₂ = 1.09 b. 0.054 mW
Explanation:
a. What is the ratio of the diameter of the first student's eardrum to that of the second student?
We know since the power is the same for both students, intensity I ∝ I/A where A = surface area of ear drum. If we assume it to be circular, A = πd²/4 where r = radius. So, A ∝ d²
So, I ∝ I/d²
I₁/I₂ = d₂²/d₁² where I₁ = intensity at eardrum of first student, d₁ = diameter of first student's eardrum, I₂ = intensity at eardrum of second student, d₂ = diameter of second student's eardrum.
Given that I₂ = 1.18I₁
I₂/I₁ = 1.18
Since I₁/I₂ = d₂²/d₁²
√(I₁/I₂) = d₂/d₁
d₁/d₂ = √(I₂/I₁)
d₁/d₂ = √1.18
d₁/d₂ = 1.09
So, the ratio of the diameter of the first student's eardrum to that of the second student is 1.09
b. If the diameter of the second student's eardrum is 1.01 cm. how much acoustic power, in microwatts, is striking each of his (and the other student's) eardrums?
We know intensity, I = P/A where P = acoustic power and A = area = πd²/4
Now, P = IA
= I₂A₂
= I₂πd₂²/4
= 1.18I₁πd₂²/4
Given that I₁ = 0.58 W/m² and d₂ = 1.01 cm = 1.01 × 10⁻² m
So, P = 1.18I₁πd₂²/4
= 1.18 × 0.58 W/m² × π × (1.01 × 10⁻² m)²/4
= 0.691244π × 10⁻⁴ W/4 =
2.172 × 10⁻⁴ W/4
= 0.543 × 10⁻⁴ W
= 0.0543 × 10⁻³ W
= 0.0543 mW
≅ 0.054 mW
Answer:
No
Explanation:
The statement is implying that if you do a certain amount of work, you're entitled to do a certain amount of work. Sometimes, work doesn't entitle you a reward.
There is no theoretical OR observational evidence for that statement.
Answer:
It would take 8.22037 hrs away. Wouldn't it?
Explanation:
Because
4.11016
4.11016
15
= 8.22037
Hello! I don't know if this will help you any but I worked it out, got nothing on it. So, I just had my twin help me and he had nothing either. But, this is just how to find the transformation. Seems like this is already complete to me.
To find the transformation, compare the equation to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.
Parent function : y=√a
Horizontal shift : None
Vertical shift : none
Reflection about the x-axis : none
Vertical stretch : Stretched.
I am so sorry if this doesn't help you but to me, in both my eyes and my brother's eyes, this already looks complete. I hope this helps you out. Again, so sorry if it doesn't.
-Karleif ☺
