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Anna71 [15]
3 years ago
13

The top of the cylinder head is sealed by the

Physics
2 answers:
zepelin [54]3 years ago
6 0

Answer:

Valve Cover

Explanation:

I've taken test

svetlana [45]3 years ago
3 0
The common name is valve cover, so the correct answer is A.
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PLZ ANSWER ASAP!!!!!!!
jenyasd209 [6]

Explanation:

It is given that,

Mass of platinum bar, m = 750 g

Length of the bar, l = 5 cm

Breadth of the bar, b = 4 cm

Width of the bar, h = 1.5 cm

Volume of the bar, V=l\times b\times h

V=5\times 4\times 1.5=30\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{750\ g}{30\ cm^3}

d=25\ g/cm^3

So, the density of the platinum bar 25\ g/cm^3. Hence, this is the required solution.

4 0
2 years ago
What is the momentum of a 50 kg object traveling 200 m/s
garik1379 [7]
Momentums equation is just p=mv
mass times velocity so 50x200
p=10,000
3 0
2 years ago
Scientific notation. jst 11a
coldgirl [10]

Answer:

2 * 10^4

Explanation:

(3 * 10^4)(4 * 10^4) / (6 * 10^4)

= (12 * 10^8)/(6 * 10^4)

= 2 * 10^4

5 0
2 years ago
(a) A 1.00-μF capacitor is connected to a 15.0-V battery. How much energy is stored in the capacitor? ________ μJ (b) Had the ca
gulaghasi [49]

Answer:

(a) E_{ c} = 112.5 \mu J

(b) E'_{ c} = 18 \mu J

Solution:

According to the question:

Capacitance, C = 1.00\mu F = 1.00\times 10^{- 6} F

Voltage of the battery, V_{b} = 15.0 V

(a)The Energy stored in the Capacitor is given by:

E_{c} = \frac{1}{2}CV_{b}^{2}

E_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 15.0^{2}

E_{ c} = 112.5 \mu J

(b) When the voltage of the battery is 6.00 V, the the energy stored in the capacitor is given by:

E'_{c} = \frac{1}{2}CV'_{b}^{2}

E'_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 6.0^{2}

E'_{ c} = 18 \mu J

6 0
3 years ago
A student drew the following model:
Gelneren [198K]

Answer: C Tectonic Plates

Explanation:

8 0
3 years ago
Read 2 more answers
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