Answer:
The weight of object in alcohol is, W₀ = 9.6 N
Explanation:
Given,
The weight of body in air, Wₐ = 10 N
The weight of the body in water, Wₓ = 9.5 N
The density of the alcohol, ρ = 0.8 g/cm³
= 800 kg/m³
The weight of body in water = weight of object in air - weight of water displaced
9.5 N = 10 N - weight of water displaced
Weight of water displaced = 0.5 N
The mass of the displaced water, m = 0.5 / 9.8
= 0.051 kg
Therefore the volume of the water displaced,
V = m / ρ
= 0.051 / 1000
= 5.1 x 10⁻⁵ m³
<em>The volume of water displaced is equal to the volume of alcohol displaced</em>
Therefore, the mass of the alcohol displaced, = V x ρ
= 5.1 x 10⁻⁵ x 800
= 0.0405 kg
The weight of the alcohol displaced, w = 0.0405 x 9.8
= 0.4 N
Therefore,
The weight of body in alcohol = weight of object in air - weight of alcohol displaced
W₀ = W - w
= 10 N - 0.4 N
= 9.6 N
Hence, the weight of object in alcohol is, W₀ = 9.6 N
