Answer:
false
Explanation:
The average reaction time for humans is 0.25 seconds to a visual stimulus, 0.17 for an audio stimulus, and 0.15 seconds for a touch stimulus.
<span>If "m" balls are thrown per second, the time taken for a ball to reach its maximum height will be 1/m seconds. How to get this? See that the next ball is thrown only when the previous ball reaches its maximum height. If 'm' balls were thrown in 1 second this means that each ball was attaining its maximum ht in 1/m seconds.
This was the main part. Now we can proceed to find maximum height in 2 ways-
a)
We know for upward journey ,
t=1/m
a=-g
v=u-gt
final velocity ,v = 0 (at highest point)
u
=gt = g/m
Now we can apply
h=ut-1/2 gt^2
Putting the values of u,t, we will get
h= g/2m^2
b)
The second method uses a trick that time taken to reach the maximum ht is same as time taken to fall down.
So, we will now consider the downward journey of ball which also takes 1/m seconds
We apply
h=ut+1/2gt^2
Here u=0 ,t=1/m
We will again get ,
h=g/2m^2</span>
Answer:
The spring constant of this spring is 200 N/m.
Explanation:
Given:
Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]
Stretched length of the spring (x₁) = 18 cm = 0.18 cm
Force acting on the spring (F) = 16 N
Spring constant of the spring (k) = ?
First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.
So, Change in length = Final length - Initial length
![\Delta x = x_1-x_0=0.18-0.10=0.08\ m](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%20x_1-x_0%3D0.18-0.10%3D0.08%5C%20m)
Now, restoring force acting on the spring is directly related to its elongation or compression as:
![F=k\Delta x](https://tex.z-dn.net/?f=F%3Dk%5CDelta%20x)
Rewriting in terms of 'k', we get:
![k=\dfrac{F}{\Delta x}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7BF%7D%7B%5CDelta%20x%7D)
Now, plug in the given values and solve for 'k'. This gives,
![k=\frac{16\ N}{0.08\ m}\\\\k=200\ N/m](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B16%5C%20N%7D%7B0.08%5C%20m%7D%5C%5C%5C%5Ck%3D200%5C%20N%2Fm)
Therefore, the spring constant of this spring is 200 N/m.
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