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Aleksandr-060686 [28]

3 years ago

12

Identify the region in the image where lighter elements, such as hydrogen or helium, are more likely to be found in a liquid or

gaseous state.

2 answers:

otez555 [7]3 years ago

4 0

Answer:

Further out (Jupiter to Pluto)

Explanation:

Annette [7]3 years ago

3 0

Lower in an arrangement

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An instructor’s laser pointer produces a beam of light with a circular cross section of diameter 0.900 mm and a total power outp

il63 [147K]

Answer:

$E_0 = 2180.53N/C.$

$B_0 = 7.27*10^{-6}T.$

$U_{avg} = 4.2*10^{-5}J/m^3.$

Explanation:

The Intensity $I$ of the beam is

$I = P /A$

The diameter of the beam is 0.900mm; therefore, the area is

$A = \pi( \dfrac{0.900*10^{-3}}{2} )^2$

$A = 6.36*10^{-7}m^2$

and since $P = 4.00*10^{-3}W$ , the intensity of the beam is

$I = \dfrac{4.00*10^{-3}W}{6.36*10^{-7}m^2}$

$\boxed{I = 6289.3W/m^2.}$

Now, the intensity $I$ is related to $E_0$ by the relation

$I = \dfrac{E_0^2}{2\mu_0 c}$

solving for $E_0$ we get

$E_0 = \sqrt{2\mu_0 c I}$

putting in the numbers we get:

$E_0 = \sqrt{2(1.26*10^{-6}) (3*10^8) (6289.3)}$

$\boxed{E_0 = 2180.53N/C.}$

The amplitude of magnetic field $B_0$ is related to $E_0$ by

$B_0 = \dfrac{E_0}{c}$

putting in numerical values we get:

$B_0 = \dfrac{2180.53}{3*10^8}$

$\boxed{B_0 = 7.27*10^{-6}T. }$

The average energy density of the laser light is

$U_{avg} = \epsilon_0 E_0^2$

$U_{avg} = (8.85*10^{-12}) (2180.53)^2$

$\boxed{U_{avg} = 4.2*10^{-5}J/m^3.}$

8 0

4 years ago

An object traveling around another object in space is in what?

Gnoma [55]

Answer:

is called an orbit

Explanation:

a satellite is any natural or artificialobject that revolves around an object in space, just as the moon revolvesaround Earth.

8 0

3 years ago

A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total

Anna007 [38]

When it comes to this equation, I always stick to good ol' momma bears solutions! Tell that boy to put the rock down, rocks are dangerous!! From- MommaBoi101

6 0

3 years ago

How do I find net force when something has arrows all four directions with different N values for each?

Nimfa-mama [501]

In the vertical direction, take up to be positive and down to be negative. Then the net <u>vertical</u> force would be

5120 N - 4050 N = 1070 N

(it's positive, so the net vertical force is pointing upward)

In the horizontal direction, take right to be positive and left to be negative. Then the net <u>horizontal</u> force would be

950 N - 1520 N = -570 N

(negative means the net horizontal force points to the left)

So the net force on the balloon is the vector

<em>F</em> = (1070 N) <em>i</em> + (-570 N) <em>j</em>

(where <em>i</em> and <em>j</em> are the unit vectors in the horizontal and vertical directions, respectively)

The magnitude of the net force on the balloon is the magnitude of this vector:

<em>F</em> = √((1070 N)² + (-570 N)²)

<em>F</em> ≈ 1212 N

8 0

3 years ago

What is the force on object exerts on another?<br>

vagabundo [1.1K]

Normal contact force

3 0

4 years ago