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Aleksandr-060686 [28]
3 years ago
12

Identify the region in the image where lighter elements, such as hydrogen or helium, are more likely to be found in a liquid or

gaseous state.
Physics
2 answers:
otez555 [7]3 years ago
4 0

Answer:

Further out (Jupiter to Pluto)

Explanation:

Annette [7]3 years ago
3 0

Lower in an arrangement

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What type of energy does gasoline have? How could you relate it to the movement of a vehicle that uses it?
Licemer1 [7]

Answer:

Chemical potential energy is the energy stored in the chemical bonds of a substance. The various chemicals that make up gasoline contain a large amount of chemical potential energy that is released when the gasoline is burned in a controlled way in the engine of the car.

Explanation:

5 0
3 years ago
A _____ line on a typical Speed vs. Time graph means an object is experiencing a constant speed.
stepladder [879]
D.horizontal has better speed
7 0
4 years ago
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11) The total conversion of 2.50 kilogram of the
Elanso [62]

1.41 × 10³⁰ MeV

As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).

Given mass = 2.5 kgs

∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J

As our answer is in joules so we have to convert it into mega electron volt(MeV)

1 J = 6.242 × 10¹² MeV

⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV

⇒1.41 × 10³⁰ MeV

If you want to learn more about mass-energy conversions then you can check out this link:

https://brainly.in/question/9760064

3 0
2 years ago
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Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di
kirill115 [55]

The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

  • time of fall of the first ball, t = 1 s
  • time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m

The distance traveled by the second ball is calculated as follows;

h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

3 0
2 years ago
An astrophysicist mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them
Alexandra [31]

Answer:

1 / i + 1 / o = 1 / f     thin lens equations

i = o f / (o - f)   rearranging

Lens 1:   object = 30 cm    f = 15.2 cm

i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm

o2 = 40.2 - 30/8 = 9.4 cm    distance of image 1 from lens 2

i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm

The final image is 24.6 cm to the left of lens 2

The first image is inverted

The second image is erect (as seen from the first image)

So the final image is inverted

M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69

7 0
3 years ago
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