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Dovator [93]
4 years ago
12

What is impulse? How does this relate to momentum?

Physics
1 answer:
lawyer [7]4 years ago
4 0
Impulse is a force acting briefly on a body and producing a finite change of momentum.
This relates to momentum because impulse is a change in momentum. Impulse = momentum. Since force is a vector quantity, impulse is also a vector in the same direction. Impulse applied to an object produces equivalent vector change in its linear momentum, also in the same direction. m•(triangle)v
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A student on a tower 49 m height drops a stone. One second later he throws a second stone after the first. They both hit the gro
ohaa [14]

By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.

<h3>How to determine the speed?</h3>

First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:

S = ut + ½gt²

49 = 0(t) + ½ × 9.8 × t²

49 = 4.9t²

t² = 49/4.9

t = √10

t = 3.16 seconds.

Now, we can determine the speed at which he threw the second stone:

<u>Note:</u> Time = 3.16 - 1 = 2.16 seconds.

S = ut + ½gt²

49 = u(2.16) + ½ × 9.8 × 2.16²

49 = 2.16u + 22.86

2.16u = 49 - 22.86

u = 26.14/2.16

u = 12.10 m/s.

Read more on initial speed here: brainly.com/question/19365526

#SPJ1

6 0
2 years ago
Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.4 m from the slits. The center of the 3
VARVARA [1.3K]

Answer:

Part a)

f = 4.76 \times 10^{14} Hz

Part b)

d = 3.48 \times 10^{-4} m

Part c)

\theta = 0.311 degree

Explanation:

Part a)

As we know that the speed of light is given as

c = 3 \times 10^8 m/s

\lambda = 630 nm

now the frequency of the light is given as

f = \frac{c}{\lambda}

so we have

f = \frac{3 \times 10^8}{630 \times 10^{-9}}

f = 4.76 \times 10^{14} Hz

Part b)

Position of Nth maximum intensity on the screen is given as

y_n = \frac{n\lambda L}{d}

so here we know for 3rd order maximum intensity

y_3 = 0.76 cm

n = 3

L = 1.4 m

0.76 \times 10^{-2} = \frac{3(630 \times 10^{-9})(1.4)}{d}

d = 3.48 \times 10^{-4} m

Part c)

angle of third order maximum is given as

d sin\theta = 3 \lambda

3.48 \times 10^{-4} sin\theta = 3(630 \times 10^{-9})

\theta = 0.311 degree

8 0
3 years ago
If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70
Schach [20]

Answer:

The  radius is  R =  0.22 5 \  m

Explanation:

From the question we are told that

    The current is  I  =  61 \ A

     The  magnetic field is  B  =  1.70 *10^{-4} \  T

Generally the magnetic field produced by a current carrying conductor  is mathematically represented as

        B  =  \frac{\mu_o  *  I}{2 *  R }

=>     R  =  \frac{\mu_o  *  I  }{ 2 *  B }

Here  \mu_o is the permeability of free space with value  \mu_o  =  4\pi * 10^{-7} N/A^2

=>    R  =  \frac{  4\pi * 10^{-7}  *   61  }{ 2 *   1.70 *10^{-4} }

=>  R =  0.22 5 \  m

8 0
3 years ago
Exercise 1 - Questions 1. Hold the grating several inches from your face, at an angle. Look at the grating that you will be usin
choli [55]

Answer:

1) on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.

2)If the angle is zero we see a bright light called undispersed light

For different angles we see the colors of the spectrum

3) must be able to see the well-collimated light emission source

Explanation:

1) A diffraction grating (diffraction grating) is a surface on which a series of indentations are drawn evenly spaced.

These crevices or lines are formed by copying a standard metal net when the plastic is melted and after hardening is carefully removed, or if the nets used are a copy of the master net.

The network can be of two types of transmission or reflection, in teaching work the most common is the transmission network, on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.

The number of lines per linear mm determines which range of the spectrum a common value can be observed to observe the range of viable light is 600 and 1200 lines per mm.

2) when looking through the diffraction grating what we can observe depends on the relative angle between the eye and the normal to the network.

If the angle is zero we see a bright light called undispersed light

For different angles we see the colors of the spectrum, if it is an incandescent lamp we see a continuum with all the colors in the visible range and if it is a gas lamp we see the characteristic emission lines of the gas.

3) Before mounting the grid on the spectrometer, we must be able to see the well-collimated light emission source, this means that it is clearly observed.

The spectrometers have several screws to be able to see the lamp clearly, this is of fundamental importance in optical experiments.

3 0
4 years ago
1. If you add air to a flat tire through a single small entry hole, why does the air spread out to fill the tire?
ikadub [295]

Answer:

The tire fills up just like anything else that holds air when u pump a ball or tire up it fills all the way up cause it is a small confined space and after filling it with air the atoms of the air fill the tire up

Explanation:

7 0
3 years ago
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