What is the function of a hypothesis in the scientific inquiry process

Two stars M1 and M2 of equal mass make up a binary star system. They move in a circular orbit that has its center at the midpoin

ozzi

Answer:

V = 365643.04 m/s

Explanation:

mass of the sun = 1.99 x 10^{30} kg

mass of M1 = mass of M2 = 6.95 solar mass = 6.95 x 1.99 x 10^{30} = 13.8305x 10^{30} kg

orbital period of each star (T) = 2.20 days = 2.20 x 24 x 60 x 60 =190,080 s

gravitational constant (G) = 6.67 x 10^{-11} N m2/kg2

orbital speed (V) = $\sqrt{\frac{G(M1+M2)}{r} }$

we need to find the orbital radius (r) before we can apply the formula above and we can get it from Kepler's third law, $T^{2} = r^{3}$ x k

where

T = orbital period

r = orbital radius

k = $\frac{4n^{2} }{G(M1+M2)}$ (take note that π is shown as $n$ )

making r the subject of the formula we now have

$r = (\frac{G(M1+M2).T^{2}}{4n^{2} } )^{\frac{1}{3} }$ (take note that π is shown as $n$ )

$r = (\frac{ 6.67 x 10^{-11} ( 13.8305x 10^{30}+ 13.8305x 10^{30} )x190080^{2}}{4x3.142^{2} } )^{\frac{1}{3} }$

r = 1.38 x 10^{10} m

Now that we have the orbital radius (r) we can substitute all required values into the formula for orbital speed

orbital speed (V) = $\sqrt{\frac{G(M1+M2)}{r} }$

$V = \sqrt{\frac{6.67 x 10^{-11} ( 13.8305x 10^{30}+ 13.8305x 10^{30}}{1.38 x 10^{10} } }\\$

V = 365643.04 m/s

3 0

3 years ago

For what position of the object will a spherical concave mirror project on the screen an image smaller than the object? a. betwe

luda_lava [24]

Answer:

option (d)

Explanation:

A concave mirror always forms a real and inverted image of an object except when the object placed between pole and focus of the mirror.

When the object is placed beyond the centre of curvature, it forms a image which is smaller than the object but it is real and inverted in nature.

3 0

3 years ago

How do you identify the zero reference position for calculating mechanical potential energy? What is the most common zero refere

ANTONII [103]

<span>The zero reference position should be the position the system has the least potential energy. As an object falls, its potential energy is converted into kinetic energy. Gravity's ability to do work (potential energy) reaches zero when it hits the ground and stops falling, hence the ground is the most common zero reference position.</span>

8 0

3 years ago

What is the magnitude of the electric field at the dot in the figure? (figure 1)

blondinia [14]

The magnitude of the electric field at the dot is : 10⁴ v/m

<h3>What is electric field?</h3>

Electric field is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.

Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field

Determine the magnitude of the electric field at the dot

change in voltage = E .d

$100 - 0 = E \times ( 1 \times 10^{-2}\ m ) ----- ( 1 )$

From equation ( 1 )

The magnitude of electric field will be given as

$E = \dfrac{100 }{ ( 1 \times 10^{-2})\ }$

$E = 10^4\ \ \frac {v}{ m}$

Hence we can conclude that The magnitude of the electric field at the dot is : 10⁴ v/m

Learn more about electric field :

brainly.com/question/14372859

#SPJ4

5 0

2 years ago

You are writing a report about space travel. Where would be the best place to find information? (2 points)

Harrizon [31]

Answer: Contact the National Aeronautics and Space Association

Explanation:

The National Aeronautics and Space Association is an independent organization in US which aims to enable a safe, secure, efficient space journey and launch of new satellites, spacecraft beyond the earth's orbit. It can give better information for the space travel already conducted by the astronauts. Thus will help in writing the report as it is the best place to find the information.

5 0

3 years ago

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