All categories

3 years ago

What is the difference between an elastic and inelastic collision

Physics

1 answer:

barxatty [35]3 years ago

4 0

Answer:

In an elastic collision, the total kinetic energy is conserved, while in an inelastic collision, it is not

Explanation:

Let's define the two types of collision:

- Elastic collision: an elastic collision is a collision in which:

1) the total momentum of the system is conserved

2) the total kinetic energy of the system is conserved

Typically, elastic collisions occur when there are no frictional forces acting on the objects in the system, so that no kinetic energy is lost into thermal energy. An example of elastic collision is the collision between biliard balls.

- Inelastic collision: an inelastic collision is a collision in which:

1 ) the total momentum of the system is conserved

2) the total kinetic energy of the system is NOT conserved

In an elastic collision, part of the total kinetic energy is lost (=converted into thermal energy) due to the presence of frictional forces. An example of inelastic collision is the accident between two cars, in which part of the energy is converted into heat.

You might be interested in

Not sure what to put this under

cestrela7 [59]

family 16 cause i said so XD

5 0

3 years ago

In the problem below, what is the student showing?

Phantasy [73]

Answer:

S<em>tudent showing the volume of cube</em>

V = a³

if a = 3 cm

Then volume is a³ = 3 ×3 × 3

= 27 cm³

6 0

3 years ago

WOULUJUTUL RECIPECUIUS.

3241004551 [841]

The force between the two objects is 19.73 nN.

<u>Explanation: </u>

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider $M_{1}$ and $M_{2}$ as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

$\text {Gravitational force}=\frac{G \times M_{1} \times M_{2}}{d^{2}}$

As gravitational constant $G=6.67 \times 10^{-11} \mathrm{m}^{3} \mathrm{kg}^{-1} \mathrm{s}^{-2}$ , $M_{1}$ = 20 kg and $M_{2}$ = 100 kg, while d = 2.6 m, then

$\text {Gravitational force}=\frac{6.67 \times 10^{-11} \times 20 \times 100}{(2.6)^{2}}=\frac{6.67 \times 20 \times 10^{-9}}{6.76}$

Thus, we get finally,

$\text {Gravitational force}=19.73 \times 10^{-9} \mathrm{N}$

As we know, nano denoted by letter 'n' equals to $10^{-9}$

So the force acting between two objects is 19.73 nN.

7 0

3 years ago

if a torque of 55.0 N/m is required and the largest force that can be exerted by you is 135 N what is th e length of the lever a

Whitepunk [10]

Answer:

$r=0.41m$

Explanation:

Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

$\tau=r\times F$

Due to the definition of cross product, the magnitude of the torque is given by:

$\tau=rFsin\theta$

Where $\theta$ is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when $sin\theta$ is equal to one, solving for r:

$r=\frac{\tau}{F}\\r=\frac{55\frac{N}{m}}{135N}\\r=0.41m$

7 0

3 years ago

Ow do quantum numbers relate to electrons?

strojnjashka [21]

They enable us to dig deeper into the electron configurations by making us focus on electrons' quantum nature

3 0

3 years ago