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WITCHER [35]
3 years ago
5

Una pelota de voleibol de 0.45 kg es impactada (golpeada) por una fuerza de 80 N. ¿ Cuál es la aceleración que experimenta la pe

lota como resultado del golpe?
Physics
1 answer:
KIM [24]3 years ago
5 0

Answer:

a = 177.77 [m/s^2]

Explanation:

Este es un problema relacionado con la segunda ley de Newton. La cual nos dice que la sumatoria de fuerzas aplicada sobre un cuerpo debe ser igual al producto de la masa por la aceleración.

De esta manera tenemos:

F = m*a

F = fuerza = 80 [N]

m = masa = 0.45 [kg]

80 = 0.45 * a

a = 80 / 0.45

a = 177.77 [m/s^2]

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An electric heater rated 600 w operates 6 hours per day find the cast to operate it for 30 days , at rs. 4.00 per unit​
djverab [1.8K]

Answer:

Rs. 432*10^3 (In kilowatts per hour)

I hope it will be useful.

3 0
3 years ago
I). Mechanical energy is the sum of potential energy and kinetic energy in an object that is used to do work.
Dmitry_Shevchenko [17]

Answer:

false statement : b )  For the motion of a cart on an incline plane having a coefficient of kinetic friction of 0.5, the magnitude of the change in kinetic energy equals the magnitude of the change in gravitational potential energy

Explanation:

mechanical energy = potential energy + kinetic energy = constant

differentiating both side

Δ potential energy + Δ kinetic energy = 0

Δ potential energy = -  Δ kinetic energy

first statement is true.

Friction is a non conservative force so inter-conversion of potential and kinetic energy is not possible in that case. In case of second  option,  the correct relation is as follows

change in gravitational potential energy = change in kinetic energy + work done against friction .

So given 2 nd  option is incorrect.

In case of no change in gravitational energy , work done is equal to

change in kinetic energy.

4 0
3 years ago
Two forces one of 12N and another of 5N act on a body in such away that they makes an angle of 90 digre with each other,what is
ELEN [110]

Answer:

Sorry I didn't know the answer

6 0
3 years ago
A 26-kg sled is on a snow-covered slope. The coefficients of friction between the sled’s runners and the snow are µs = 0.096 and µ
sweet-ann [11.9K]

Answer:

Explanation:

Given

mass of sled =26 kg

coefficient of static friction \mu _s=0.096

coefficient of kinetic friction \mu _k=0.072

In order to move sled from rest we need to provide a force greater than static friction which is given by

f_s=\mu mg=0.096\times 26\times 9.8=24.46 N

After Moving Sled kinetic friction comes in to play which is less than static friction

f_k=\mu _kmg=0.072\times 26\times 9.8=18.34 N

therefore minimum force to keep moving sledge at constant velocity is 18.34 N

3 0
3 years ago
Define pressure in short
Makovka662 [10]

Answer:

hope it helps......

Explanation:

Pressure, in the physical sciences, the perpendicular force per unit area, or the stress at a point within a confined fluid.

7 0
3 years ago
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