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3 years ago

How do very long radio waves reach stations beyond the curvature of the Earth?

2 answers:

8 0

They actually bounce off a charged layer of atmosphere to reach stations beyond the curvature of the Earth. The correct option among all the options that are given in the question is the last option or option "d". The radio waves bounce off the ions present in the ionosphere of earths atmosphere and reach stations beyond the curvature of Earth.

Drupady [299]3 years ago

5 0

The correct answer for the question that is being presented above is this one: "d. They bounce off a charged layer of the atmosphere." Very long radio waves reach stations beyond the curvature of the Earth. They bounce off a charged layer of the atmosphere<span>
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How does Newton's second law of motion gives the measurement of force?

Alex Ar [27]

Hi pupil here's your answer ::

_____________________________

How does Newton's second law of motion gives the measurement of force?
So the answer is first : what is newton's second law? =》The rate of change of momentum of an object is equivalent to particular direction of the FORCE
=> This is how Newton's second law of motion gives the measurement of FORCE .

=>It gives measurement as the equation
》 F=MA《
Where F is force , M is mass of the object , and A is the acceleration produced .

_____________________________

hope that it helps. . . . . .

7 0

2 years ago

A railroad car of mass 2.50*10^4 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railroa

NemiM [27]

Answer:

(a) 2.5 m/s

(b) 37.5 KJ

Explanation:

(a)

From the law of conservation of momentum, Initial momentum=Final momentum

$mV_1+3mV_2=(m+3m)V_f=4mV_f$

$V_1+3V_2=4V_f$ and making $V_f$ the subject then

$V_f=\frac {V_1+3V_2}{4}$ and since $V_1$ is initial velocity of car, value given as 4 m/s, $V_2$ is the initial velocity of the three cars stuck together, value given as 2 m/s and $v_f$ is the final velocity which is unknown. By substitution

$V_f=\frac {4+(3\times2)}{4}=2.5 m/s$

(b)

Initial kinetic energy is given by

$\frac {mV_1^{2}}{2}+\frac {3mV_2^{2}}{2}=\frac {m(V_1^{2}+3V_2^{2}}{2}=\frac {2.5\times 10^{4}(4^{2}+3(2^{2}))}{2}=350\times10^{3} J= 350 KJ$

Final kinetic energy is given by

$\frac {4mV_f^{2}}{2}=\frac {4\times 2.5\times 10^{4}\times 2.5^{2}}{2}=312.5\times 10^{3} J=312.5 KJ$

The energy lost is given by subtracting the final kinetic energy from the initial kinetic energy hence

Energy lost=350-312.5=37.5 KJ

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3 years ago

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A 0.125 kg hockey puck moving at 20.0 m/s is caught and held by an 85.0 kg goalkeeper at rest. After catching the puck, with wha

jenyasd209 [6]

Answer:

Explanation:cuz i saiad so

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3 years ago

If a girl is standing in front of a smooth surface from which a sound is reflected the girl may hear

Harlamova29_29 [7]

If the girl is also near the source of the sound, two alike sets of sounds will be heard.

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3 years ago

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Which switch configuration creates a short circuit?

lara31 [8.8K]

I think the answer would be Switch 1 open; switches 2, 3, and 4 closed. It is letter D. This will happen when there is a low resistance and a high circuit so from the choices above, when two bulbs are open and one bulb is close, so there is a low resistance and high voltage.

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3 years ago