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Makovka662 [10]
3 years ago
8

How do very long radio waves reach stations beyond the curvature of the Earth?

Physics
2 answers:
lisov135 [29]3 years ago
8 0
They actually bounce off a charged layer of atmosphere to reach stations beyond the curvature of the Earth. The correct option among all the options that are given in the question is the last option or option "d". The radio waves bounce off the ions present in the ionosphere of earths atmosphere and reach stations beyond the curvature of Earth.
Drupady [299]3 years ago
5 0
The correct answer for the question that is being presented above is this one: "d. They bounce off a charged layer of the atmosphere." Very long radio waves reach stations beyond the curvature of the Earth. They bounce off a charged layer of the atmosphere<span>
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a car that is moving in a straight line has an acceleration of 8.0 m/s/s for 4.0 seconds. which one of the following is true of
Nuetrik [128]

Answer:

32 ms

Explanation:

v=32ms.

Explanation:

I will assume that you mean that the acceleration is 8.0 ms2, as 8.0ms is a value for velocity, not acceleration.

Here, we use the formula v=u+at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is time. Let's substitute values, then:

v=u+at,

v=0+8.0⋅4.0

v=32,

v=32ms.

Hope it Helps! :D .

7 0
3 years ago
A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
Brut [27]

Answer:

  • The gravity does a work of - 117.6 Joules.
  • The tension does not do work as the force is perpendicular to the direction of motion at any point in the trajectory.

Explanation:

The work done by the gravity simply is the difference in gravitational potential energy multiplied by -1:

W_g = - \Delta E_p = - (mgh_f  - m g h_i)

where m is the mass of the ball, g is the acceleration due to gravity, h_f is the final height and h_i is the initial height.

So, if the radius is 2.00 m, then the difference of height will be 4 meters:

W_g = - mg (h_f - h_i)

W_g = - 3.00 \ kg \ 9.8 \frac{m}{s^2} \ 4 \m

W_g = - 117.6 Joules

As the tension is perpendicular to the velocity of the ball, the force is always perpendicular to the direction of motion. So, the differential of work will be:

dW = \vec{F}  d\vec{r} = 0

6 0
3 years ago
A.) Determine the work done by Zach on the bull.
Lana71 [14]

Explanation:

Work done is a physical quantity that is defined as the force applied to move a body through a particular distance.

Work is only done when the force applied moves a body through a distance.

    Work done  = Force x distance

The maximum work is done when the force is parallel to the distance direction.

The minimum work is done when the force is at an angle of 90° to the distance direction.

 So to solve this problem;

 multiply the force applied by Zack and distance through which the bull was pulled.

3 0
3 years ago
Which one of the statements below is true about mechanical waves?
TEA [102]
They require a medium to travel through
5 0
3 years ago
The rainbow is a result of a. Diffraction of the light.
suter [353]

Rainbows are caused by the dispersion of light, which itself consists of a combination of refraction and reflection of light around little droplets of water.

Choice C

5 0
3 years ago
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