Maybe 47.999 g if I can’t I’m sorry.
Alkaline solutions are basic so answer is C basic
First we must write a balanced chemical equation for this reaction

The mole ratio for the reaction between
and
is 1:2. This means 1 moles of
will neutralize 2 moles
. Now we find the moles of each reactant based on the mass and molar mass.



The
was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.
<u>Answer:</u> The molarity of anions
in the solution is 0.0316 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Given mass of iron (II) chloride = 0.10 g
Molar mass of iron (II) chloride = 126.75 g/mol
Volume of solution = 50 mL
Putting values in above equation, we get:

1 mole of iron (II) chloride produces 1 mole of
ions and 2 moles of
ions
So, concentration of chloride ions (anions) in the solution = 
Hence, the molarity of anions
in the solution is 0.0316 M
Answer:
3.01×10²⁶ molecules
Explanation:
From the question given above, the following data were obtained:
Mass of H₂ = 1 Kg
Number of molecules =?
From Avogadro's hypothesis,
1 mole of H₂ = 6.02×10²³ molecules
But 1 mole of H₂ = 2 × 1 = 2 g
Now, we shall determine the number of molecules present in 1 Kg (i.e 1000 g) of H₂ as follow:
From Avogadro's hypothesis,
2 g of H₂ = 6.02×10²³ molecules
Therefore,
1000 g of H₂ = 1000 × 6.02×10²³ / 2
1000 g of H₂ = 3.01×10²⁶ molecules
Thus, the number of molecules present in 1 Kg (i.e 1000 g) of H₂ is 3.01×10²⁶ molecules