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4 years ago

What does the graph of acceleration vs. time look like for something going a

Physics

1 answer:

UkoKoshka [18]4 years ago

7 0

Acceleration vs time graph would show C. A horizontal line (at zero)

Explanation:

The acceleration of an object is the rate of change of velocity of the object:

$a=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in velocity

$\Delta t$ is the time interval

For an object moving at constant velocity,

$\Delta v = 0$

This means that also the acceleration is zero:

$a=0$

And therefore, if we plot the graph of the acceleration vs time, we would see a horizontal line (cosntant acceleration) at zero (because the acceleration is zero).

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

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More recent findings of children with exceptionally high IQs _

Alenkasestr [34]

Answer:

Explanation:

Researchers and educators differ in how they define gift-

edness. Traditionally, researchers have defined giftedness

as high general intelligence as measured by a high global

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Exceptionally intelligent students (hereafter referred to

as gifted students) face a variety of problems in ordinary

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and weird and are labeled as nerds and geeks (Silverman,

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3 years ago

Hannah bought a potted rose plant. She’s looking for a place to put it. Where is the rose plant most likely to thrive?

zavuch27 [327]

Answer: C. )in the backyard with bright sunlight

Explanation: its better for the rose plant.

6 0

4 years ago

At what distance along the z-axis is the electric field strength a maximum?

Lesechka [4]

The axial field is the integration of the field from each element of charge around the ring. Because of symmetry, the field is only in the direction of the axis. The field from an element ds in the ring is

dE = (qs*ds)cos(T)/(4*pi*e0)*(x^2 + R^2) 

where x is the distance along the axis from the plane of the ring, R is the radius of the ring, qs is the linear charge density, T is the angle of the field from the x-axis. 

However, cos(T) = x/sqrt(x^2 + R^2) 

so the equation becomes 

dE = (qs*ds)*[x/sqrt(x^2 + R^2)]/(4*pi*e0)*(x^2 + R^2) 

dE =[qs*ds/(4*pi*e0)]*x/(x^2 + R^2)^1.5 

Integrating around the ring you get 

E = (2*pi*R/4*pi*e0)*x/(x^2 + R^2)^1.5 

E = (R/2*e0)*x*(x^2 + R^2)^-1.5 

we differentiate wrt x, the term R/2*e0 is a constant K, and the derivative is 

dE/dx = K*{(x^2 + R^2)^-1.5 +x*[(-1.5)*(x^2 + R^2)^-2.5]*2x} 

dE/dx = K*{(x^2 + R^2)^-1.5 - 3*x^2*(x^2 + R^2)^-2.5} 

to find the maxima set this = 0, giving 

(x^2 + R^2)^-1.5 - 3*x^2*(x^2 + R^2)^-2.5 = 0 

mult both side by (x^2 + R^2)^2.5 to get 

(x^2 + R^2) - 3*x^2 = 0 

-2*x^2 + R^2 = 0 

-2*x^2 = -R^2 

x = (+/-)R/sqrt(2)

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4 years ago

What is the relationship between the valence electrons of an atom and the chemical bonds the atom can form?

stellarik [79]

Answer:

Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.

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3 years ago

The speed of a sound wave depends on....

Hitman42 [59]

The answer you’re looking for is
D. the frequency

7 0

3 years ago

Read 2 more answers