Answer:
(a) 92 %
(b) 6.76 %
Explanation:
length, l = 4 m, height, h = 5 m, width, w = 3 m, density of water = 1000 kg/m^3
density of ice = 920 kg/m^3, density of mercury = 13600 kg/m^3
(a) Let v be the volume of ice below water surface.
By the principle of flotation
Buoyant force = weight of ice block
Volume immersed x density of water x g = Total volume of ice block x density
of ice x g
v x 1000 x g = V x 920 x g
v / V = 0.92
% of volume immersed in water = v/V x 100 = 0.92 x 100 = 92 %
(b) Let v be the volume of ice below the mercury.
By the principle of flotation
Buoyant force = weight of ice block
Volume immersed x density of mercury x g = Total volume of ice block x
density of ice x g
v x 13600 x g = V x 920 x g
v / V = 0.0676
% of volume immersed in water = v/V x 100 = 0.0676 x 100 = 6.76 %
